我目前正在使用Slim和Ajax来开发移动应用程序。在我的数据库中,我有一个列存储登录的会话代码。我需要能够登录后,比较输入到数据库的用户名并根据它检索sessionCode。
我目前的PHP是:
$app->post('/logIn/', 'logIn');
function logIn()
{
$request = \Slim\Slim::getInstance()->request();
$q = json_decode($request->getBody());
//$hashedPassword = password_hash($q->password, PASSWORD_BCRYPT);
$sql = "SELECT * FROM users where username=:username AND password=:password";
try {
$db = getConnection();
$stmt = $db->prepare($sql);
$stmt->bindParam("username", $q->username);
$stmt->bindParam("password", $q->password);
$stmt->execute();
//$row=$stmt->fetch(PDO::FETCH_ASSOC);
$row=$stmt->fetch(PDO::FETCH_OBJ);
//$verify = password_verify($q->password, $row['password']);
$db = null;
echo json_encode($row);
} catch (PDOException $e) {
echo $e->getMessage();
}
} //PHP 5.4 LogIn
$app->get('/getSessionCode/:username','getSessionCode');
function getSessionCode($username)
{
$request = \Slim\Slim::getInstance()->request();
$q = json_decode($request->getBody());
$sql = "SELECT * FROM users WHERE username=:username";
try{
$db = getConnection();
$stmt = $db->prepare($sql);
$stmt->bindParam("username", $username);
$stmt->execute();
$row=$stmt->fetchALL(PDO::FETCH_OBJ);
$dbh=null;
echo json_encode($row);
}
catch(PDOException $e){
if(db != null) $db = null;
echo $e->getMessage();
}
}
Ajax代码:
$("#checkLogIn").click(function()
{
username = $("#enterUser").val();
$.ajax({
type: 'POST',
contentType: 'application/json',
url: rootURL + '/logIn/',
dataType: "json",
data: checkLogIn(),
success: function(data)
{
if(data != false)
{
$.ajax({
type: 'GET',
url: rootURL + "/getSessionCode/" + username,
dataType: "json",
success: sessionData
});
}
else
{
alert("Username and/or Password was incorrect");
}
}
})
});
function checkLogIn(data)
{
return JSON.stringify({
"username": $("#enterUser").val(),
"password": $("#enterPass").val(),
});
}
function sessionData(data){
session = data.sessionCode;
alert(username);
alert(session);
$.mobile.changePage("#mainMenu");
}
当我运行应用程序并登录时。它运行虽然没问题但是当它到达警报(会话)时它返回undefined。我将会话和用户名全局设置为变量,这不是问题,当它达到警报(用户名)时,它返回我输入的用户名。
答案 0 :(得分:0)
我能够通过在sessionData函数中添加for循环来解决我的问题
function sessionData(data){
for(var i = 0; i < 1; i++)
{
sessionStorage.code = data[i].sessionCode;
}
$.mobile.changePage("#mainMenu");
}