向node.js服务发送请求会导致超时

Question

了解node.js并开发了一个简单的服务：

// set up ======================================================================
var express = require('express');
var app = express();                               // create our app w/ express
var port = process.env.PORT || 8080;                // set the port

var bodyParser = require('body-parser');
//var methodOverride = require('method-override')
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({extended: true}));

app.use(function (req, res, next) {
    //the code hits this point!
    var data = '';
    req.on('data', function (chunk) {
        data += chunk;
    });
    req.on('end', function () {
        req.rawBody = data;
        next();
    });
    //console.log(data);
});
//app.use(methodOverride());
// routes ======================================================================
require('./routes.js')(app);

// listen (start app with node server.js) ======================================
app.listen(port);
console.log("App listening on port " + port);

routes.js

var _ = require('underscore');

module.exports = function (app) {
    app.post('/', function (req, res) {
        var Validator = require('jsonschema').Validator;
        var v = new Validator();
        var jso = req.rawBody;
        var newjso = JSON.parse(req.rawBody);
        var schema={
            "description": "A payload",
            "type": "object"
        };

        var result = v.validate(newjso,schema);

        console.log('----------------------payload--------------------------------------')
        console.log(newjso);
        console.log('------------------end payload--------------------')

        if (result.errors.length > 0) {
            res.setHeader('content-type', 'application/json');
            res.status(400);
            res.json({
                "error": "Could not decode request: JSON parsing failed"
            });
            console.log('------------------ERROR!!!--------------------')
        }
        else
        {
            var resp = _.filter(_.where(newjso.payload, {drm: true}), function (item) {
                return item.episodeCount > 0
            });

            var newArray = [];
            resp.forEach(function (item) {
                var newItem = _.pick(item, 'image', 'slug', 'title');
                newItem.image = _.propertyOf(newItem.image)('showImage');
                newArray.push(newItem);
            })

            res.setHeader('content-type', 'application/json');
            res.status(200);
            res.json({response: newArray});
        }
    })
}

当我将这个或任何其他json发布给邮递员时：

{
  "payload": [
    {
    }]
}

当指定Contenttypeheader = application / json时，它看起来是超时的。为什么它超时，如何在我的node.js程序中解决这个问题？

Answer 1

这是因为bodyParser.json()已经解析了整个请求，因此end永远不会在您的自定义中间件中触发。同样，我不知道你为什么要尝试捕获原始请求，而你所做的只是将其传递给JSON.parse()，这就是bodyParser.json()已经做过的事情。