Question

我想知道是否有办法将日期分为2014-01-26 05：39：29.000和2014-01-26 07：45：31.000，计算一天。我目前有以下代码，只按其唯一的日期时间对它们进行分组。

    SELECT ETK_ExpirationDateTime, COUNT(*) as TotalRows
    FROM History_Action 
    WHERE [State] = 4
    GROUP BY ETK_ExpirationDateTime
    ORDER BY ETK_ExpirationDateTime

我是否可以通过演员或其他方式将上述2个日期显示为一行总额？

Answer 1

SELECT CAST(ETK_ExpirationDateTime AS DATE) AS DATE, COUNT(*) as TotalRows
FROM History_Action 
WHERE [State] = 4
GROUP BY CAST(ETK_ExpirationDateTime AS DATE)
ORDER BY 1

Answer 2

您可以使用转化日期：

SELECT CONVERT(date, ETK_ExpirationDateTime) as ExpirationDateTime, COUNT(*) as TotalRows
FROM History_Action 
WHERE [State] = 4
GROUP BY CONVERT(date, ETK_ExpirationDateTime)
ORDER BY CONVERT(date, ETK_ExpirationDateTime)

这仅适用于SQL 2008或更高版本。对于旧版本的SQL，您可以使用一些棘手的操作：

SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, ETK_ExpirationDateTime)) as ExpirationDateTime, COUNT(*) as TotalRows
FROM History_Action 
WHERE [State] = 4
GROUP BY DATEADD(dd, 0, DATEDIFF(dd, 0, ETK_ExpirationDateTime))
ORDER BY DATEADD(dd, 0, DATEDIFF(dd, 0, ETK_ExpirationDateTime))

按时间分组，没有时间

2 个答案: