我想从数组中删除子元素,例如
{
"employees": [
{
"name": "name1",
"id": "id1"
},
{
"name": "name2",
"id": "id2"
},
{
"name": "name3",
"id": "id3"
}
]
}
我需要一个补丁来删除所有ID,以便我可以做这样的事情
[{ "op": "remove", "path": "/employees/0/id"},
{ "op": "remove", "path": "/employees/1/id"},
{ "op": "remove", "path": "/employees/2/id"}]
但有没有办法指定通配符来选择数组中的所有id元素
答案 0 :(得分:0)
我一直在看JSON patch draft,但没有找到关于正则表达式的任何内容。一种解决方案是使用一些JSON
解析工具来创建它,例如jq和python-json-patch。第一个删除所有id
个键,第二个键从diff创建一个补丁,使用如下:
jq 'del(.employees[].id)' jsonfile | jsondiff jsonfile -
它产生:
[{"op": "replace", "path": "/employees/2", "value": {"name": "name3"}},
{"op": "replace", "path": "/employees/1", "value": {"name": "name2"}},
{"op": "replace", "path": "/employees/0", "value": {"name": "name1"}}]
还使用jsonpatch
工具应用补丁,它似乎生成了正确的输出,如:
jq 'del(.employees[].id)' jsonfile | jsondiff jsonfile - | jsonpatch jsonfile -
它产生:
{"employees": [{"name": "name1"}, {"name": "name2"}, {"name": "name3"}]}