python（2.7）函数接受多个整数和一个列表，并返回一个整数和一个列表

Question

如果您看到下面的players.py文件代码，则会将三个整数和一个列表用作first_player（）的输入参数。我希望函数返回一个列表和一个整数（我只需要一个返回）。但是我只得到一个空列表。在这种情况下，如何调用列表和整数？

def dealing():

    player1 = list()
    start_drawing = 0
    nc = 0
    cards = L_shuffle_deck.shuffle_deck()
    n = len(cards) - 1 # n = 51    
    while start_drawing < 2:
        players.first_player(player1, n, nc, cards)
        start_drawing += 1
        nc += 1

    print player1

    ...

players.py下面..

def first_player(player1, n, nc, cards):

    player1 = player1 + [cards[n]]                   
    card_order = player1                             
    changing = conv_cards.assigning(nc, card_order)  
    player1[nc] = changing[nc]                       
    cards = cards[:n]                                
    n -= 1                                           

    return player1, n #doesn't work
    #I want my output to be player1(list), n(integer)

Answer 1

从粗略看一下您的代码，您似乎从函数中返回值，但您不会将这些值分配给任何变量。

在dealing函数中尝试此操作：

...
player1, n = players.first_player(player1, n, nc, cards)
...