Question

我不明白为什么这种方法不起作用。它编译，但会引发运行时错误。

这是代码。这是一个Pig Latin-izer。它应该将短语分成单词，然后格式化这些单词，然后将它们全部放回到一个ArrayList中（稍后我可能会更改它。）我不明白为什么这不能正常运行。

import java.util.*;
public class OinkerSpine 
{
    public ArrayList<String> pigLatin (String phrase)
    {
        phrase = phrase.replaceAll(".", " .");
        phrase = phrase.replaceAll(",", " ,");
        phrase = phrase.replaceAll("!", " !");
        //phrase = phrase.replaceAll("?", " ?");
        phrase = phrase.replaceAll("'", " '");

        String []words = phrase.split(" ");
        ArrayList <String> Endphrase = new ArrayList <String> ();
        final String AY = "ay";
        final String YAY = "-yay";

        String endword = "";

        for(int i=0; i < words.length; i++) 
        {
            String firstletter;
            String restofword;
            String secondletter;

            if (words[i].length() == 1)
            {
                firstletter = words[i];
                restofword = "";
            }
            else
            {
                firstletter = words[i].substring(0, 1);
                restofword = words[i].substring(1);
            }

            boolean firstIsUpper = (firstletter.equals(firstletter.toUpperCase()));

            if (firstIsUpper)
            {
                firstletter = firstletter.toLowerCase();
                secondletter = restofword.substring(0, 1);
                restofword = restofword.substring(1);

                secondletter = secondletter.toUpperCase();
                restofword = secondletter + restofword;
            }

            if (firstletter.equals("a") || firstletter.equals("e") ||
                firstletter.equals("i") || firstletter.equals("o") ||
                firstletter.equals("u"))
            {
                endword = firstletter + restofword + YAY;
            }

            else
            {
                endword = restofword + "-" + firstletter + AY;
            }

            endword = endword.replaceAll(" .", ".");
            endword = endword.replaceAll(" ,", ",");
            endword = endword.replaceAll(" !", "!");
            //endword = endword.replaceAll(" ?", "?");
            endword = endword.replaceAll(" '", "'");

            Endphrase.add(endword);
        }
        return Endphrase;
    }
}

这里有什么？

Answer 1

如果restofword或word[i]为空字符串

，会发生什么

secondletter = restofword.substring(0, 1);

或

firstletter = words[i].substring(0, 1);

Answer 2

你可能在这里替换了太多字符：

phrase = phrase.replaceAll(".", " .");

为substring留下不足的字母。你可能想要

phrase = phrase.replaceAll("\\.", " .");

或更好

phrase = phrase.replace(".", " .");

索引越界错误。为什么？

2 个答案: