我有一张表：
2 Savita EC1 50
2 Savita EC2 55
2 Savita EC3 28
2 Savita EC4 30
2 Savita EC5 60
3 Abhi EC1 40
3 Abhi EC2 38
3 Abhi EC3 35
3 Abhi EC4 45
3 Abhi EC5 37
4 Priya EC1 60
4 Priya EC2 49
4 Priya EC3 26
4 Priya EC4 29
4 Priya EC5 44
5 Shanthi EC1 70
5 Shanthi EC2 19
5 Shanthi EC3 45
5 Shanthi EC4 44
5 Shanthi EC5 50
6 Harish EC1 60
6 Harish EC2 64
6 Harish EC3 26
6 Harish EC4 28
6 Harish EC5 29
我想添加优雅标记，条件是 每个学生的总宽限标记最多为6分，如果候选人在EC1中有28个，EC2中有27个失败，那么在加上恩典EC1 = 30和EC2 = 30之后。而他是通过。如果他在EC1中有25分，在EC2中有28分，那么所需的恩典标记是5 + 2 = 7。因此他失败并且没有添加任何优雅标记，Grace标记可以添加到最多两个主题。如果他在超过2个科目中失败，那么他就失败了，没有添加任何恩典标记。 我有一个proc喜欢
create procedure SP_student3
as
begin
select FstudentName,EC1,EC2,EC3,EC4,EC5,TOTALMARKS, CASE
WHEN EC1<30 THEN 'FAIL'
WHEN EC2<30 THEN 'FAIL'
WHEN EC3<30 THEN 'FAIL'
WHEN EC4<30 THEN 'FAIL'
WHEN EC5<30 THEN 'FAIL'
ELSE 'PASS' END AS RESULT FROM(select FstudentName,EC1,EC2,EC3,EC4,EC5,TOTALMARKS=EC1+EC2+EC3+EC4+EC5 FROM Student PIVOT(SUM(FMarks) for Fsubject in ([EC1],[EC2],[EC3],[EC4],[EC5],TOTALMARKS]))ASPIVOTTABLE )B end
哪个给出了
Abhi 40 38 35 45 37 195 PASS
Harish 60 64 26 28 29 207 FAIL
Priya 60 49 26 29 44 208 FAIL
Savita 50 55 28 30 60 223 FAIL
Shanthi 70 19 45 44 50 228 FAIL
答案 0 :(得分：1)
如果我的假设是正确的，那你就是在寻找：
SELECT A.StudentName, EC1,EC2,EC3,EC4,EC5,Total,
case when failures > 6 or subjects > 2 then 'Failure'
else 'Pass' end as Result
FROM
( SELECT StudentName, EC1, EC2, EC3, EC4, EC5
FROM Student
PIVOT(sum(Marks) for subject in([EC1],[EC2],[EC3],[EC4],[EC5]))as pt) A,
( select
studentName,
sum(case when Marks < 30 then 30 - Marks else 0 end) as failures,
sum(case when Marks < 30 then 1 else 0 end) as subjects,
sum(marks) as total
from
student
group by
studentname
) B
where
A.StudentName = B.StudentName
编辑：添加了对2个主题的检查，但测试数据不包含任何此类情况。
答案 1 :(得分：1)
我对这个问题略有不同。如果向表中添加两列 - “GraceMarks”（int）和Pass（bit），则可以使用多个顺序和逻辑更新查询以及最后的简单选择来执行此操作。我在一个名为“test”的表中有这个，但你可以将其改为“学生”。
-- Find if students passed or failed the year
-- Assume students are all intitally flagged to Pass, and gracemarks are zero.
update test SET Pass=1, GraceMarks=0
-- First, any mark <=23 is a fail
update test SET Pass=0 where Mark<=23
-- if a student failed one subject, they fail them all
update test SET Pass=0 where StudentID in (
SELECT StudentID
from dbo.test
where Pass=0)
-- Next work out how many grace marks would be needed to pass each subject
update test SET GraceMarks=30-Mark where Mark<30 and Pass=1
-- If a student used more that a total of 6 grace marks, they failed too
update test SET Pass=0 where StudentID in (
SELECT StudentID
FROM dbo.Test
GROUP BY StudentID
HAVING (SUM(GraceMarks) > 6))
-- If they used grace marks in 3 or more subjects ... fail
update test SET Pass=0 where StudentID in (
SELECT StudentID
FROM dbo.Test
WHERE (GraceMarks > 0)
GROUP BY StudentID
HAVING (COUNT(GraceMarks) > 2))
-- Now show results
select StudentID, StudentName,
sum(case course when 'EC1' then mark end) as EC1,
sum(case course when 'EC2' then mark end) as EC2,
sum(case course when 'EC3' then mark end) as EC3,
sum(case course when 'EC4' then mark end) as EC4,
sum(case course when 'EC5' then mark end) as EC5,
SUM(mark) as totalMark,
CASE Pass WHEN 0 THEN 'Fail' ELSE 'Pass' END AS YearPassorFail
from dbo.Test
group by StudentID, StudentName, CASE Pass WHEN 0 THEN 'Fail' ELSE 'Pass' END
order by StudentName
此代码的输出是此表 -
3 Abhi 40 38 35 45 37 195 Pass
6 Harish 60 64 26 28 29 207 Fail
4 Priya 60 49 26 29 44 208 Pass
2 Savita 50 55 28 30 60 223 Pass
5 Shanthi 70 19 45 44 50 228 Fail
您可以添加一个名为“reason”的附加列，并更改上面的查询以包括他们失败的原因（Harish因为3个主题<30或需要7个优雅标记，Shanthi因为一个主题低于24）。
这种方法的优点是你可以看到每一步发生了什么，并且你有一个使用的通过/失败和宽限标记的记录。然后，您可以编写查询，查找诸如 - 使用了多少个宽限标记？如果恩典标记只允许在3，谁会失败？我个人也喜欢很多简单的步骤而不是一个复杂的步骤，但那可能只是我。