工头启动多个流程？

Question

我在Procfile中定义了三个流程。有时候，我只想跑两个。是否有命令？

$ foreman start process_1 process_2
ERROR: "foreman start" was called with arguments ["process_1", "process_2"]
Usage: "foreman start [PROCESS]"

Answer 1

您可以使用-c or --concurrency option，只需指定要启动的流程：

$ foreman start -c process_1=1,process_2=1

Answer 2

此参数已更新为-m / --formation

即：foreman start -m "web=1,worker=1"