根据列和行计算数据

Question

我有一个包含以下列的表：

    Date    ReportDate  Received    Answered    Average Wait Time
5/1/2015    5/3/2015    10           10           0:00:04
5/1/2015    5/3/2015    10           10           0:00:10
5/1/2015    5/3/2015    4             4           0:00:02
5/1/2015    5/3/2015    5             5           0:00:03
5/2/2015    5/3/2015    10           10           0:00:09
5/2/2015    5/3/2015    9             9           0:00:03
5/2/2015    5/3/2015    12           12           0:00:09
5/2/2015    5/3/2015    15           15           0:00:02
5/2/2015    5/3/2015    20           20           0:00:10
Total                   95           95           0:00:07

我想计算总数并根据不同的报告日期将其存储在不同的表中，例如： -

ReportDate  TotalReceivedContacts   TotalAnsweredContacts   TotalAverageWaitTime
5/3/2015        95                       95                      0:00:07

像这样我有很多基于ReportDate的行。请帮忙。

Answer 1

试试这个：

SELECT ReportDate, SUM(Received) AS TotalReceivedContacts,
    SUM(Answered) AS TotalAnsweredContacts, AVG(AverageWaitTime) AS TotalAverageWaitTime
FROM Table
GROUP BY ReportDate

Answer 2

SELECT SUM(Received) AS TotalReceivedContacts,SUM(Answered) AS   
TotalAnsweredContacts , AVG(WaitTime) AS TotalAverageWaitTime FROM  
YourTableName group by ReportDate 

试试这个：）

Answer 3

这应该有效：

    SELECT ReportDate, SUM(Received) as ReceivedSum,
           SUM(Answered) as AnsweredSum ,AVG(WaitTime) as WaitTimeAVG
    FROM a
    GROUP BY ReportDate
    ORDER BY ReportDate

请参阅SQL Fiddle

Answer 4

试试这个。

INSERT INTO another_table_name (ReportDate,TotalReceivedContacts,TotalAnsweredContacts,TotalAverageWaitTime)
SELECT ReportDate,SUM(Received) AS TotalReceivedContacts,SUM(Answered) AS        
TotalAnsweredContacts, AVG(Average Wait Time) as TotalAverageWaitTime FROM   
table_name GROUP BY ReportDate ORDER BY ReportDate

注意：＆＃34; another_table_name＆＃34;将是您数据库中的现有表，此查询将插入您从＆＃34; table_name＆＃34;中选择的所有数据。 to＆＃34; another_table_name＆＃34;。