Question

我试图通过使用ajax函数更新它来简单地更新一个布尔形式值，因为为什么我要它重新加载，但无论如何，我已经检查过我传递了csrf_token，并确保＆＃39不是问题。我认为这是我的urls.py的一个问题，但我不确定它究竟是什么。

我该怎么做才能解决此错误？

继承我的views.py for ajax表单，注意：project_complete是我模型中的booleanfield

@login_required
def ProjectDetailToDoCForm(request):
    form = ProjectToDoCForm(request.POST or None)
    if form.is_valid() and request.is_ajax():
        args = {}
        args.update(csrf(request))
        ajaxVal = request.POST.get('booleanValue')
        args['doneBool'] = ajaxVal.project_complete
        return HttpResponse(json.dumps(args), content_type="application/json")

的javascript

<script type="text/javascript">
    $(document).on("submit", "#project_edit_date", function(e){
        e.preventDefault();
        updateForm();
    });

    function updateForm() {

        function getCookie(name) {
        var cookieValue = null;
        if (document.cookie && document.cookie != '') {
            var cookies = document.cookie.split(';');
            for (var i = 0; i < cookies.length; i++) {
                var cookie = jQuery.trim(cookies[i]);
                if (cookie.substring(0, name.length + 1) == (name + '=')) {
                    cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
                    break;
                }
            }
        }
        return cookieValue;
    }  

        $.ajaxSetup({
            beforeSend: function(xhr, settings) {
                if (!(/^http:.*/.test(settings.url) || /^https:.*/.test(settings.url))) {
                    // Only send the token to relative URLs i.e. locally.
                    xhr.setRequestHeader("X-CSRFToken", getCookie('csrftoken'));
                }
            }
        });

        $.ajax({
            url: "{% url 'projects:todoc_form' %}",
            type: "POST",
            datatype: "json",
            data: {booleanValue : $("#id_project_complete").val()},

            "beforeSend": function(xhr, settings) {
                console.log("Before Send");
                $.ajaxSettings.beforeSend(xhr, settings);
            },

            success: function(json){
              console.log(json);
              console.log("success");
            },

            error:function(xhr,errmsg,err){
                console.log(err);
            }
        });
    }
</script>

形式

<form action="" method="post" id="project_edit_date">{% csrf_token %}
   <label for="todoc">Task Done?</label>
   <span name="todoc" id="check_done">   {{todocform.project_complete}}</span>
   <button type="submit" id="project_edit_button">
        <span>Update</span>
   </button>
</form>

urls.py

urlpatterns = patterns('',
    url(r'^$', views.ProjectView.as_view() , name='project'),
    url(r'^create/$', views.createproject, name='create'),
    url(r'^edit/(?P<slug>[\w-]+)/$', views.ProjectDetail.as_view(), name='indproject'),
    url(r'^view/(?P<slug>[\w-]+)/$', views.ProjectDetailPublic.as_view(), name='pproject'),
    url(r'^form/(?P<slug>[\w-]+)/$', require_POST(ProjectDetailForm.as_view()), name='indproject_form'),
    url(r'^update/(?P<slug>[\w-]+)/$', require_POST(ProjectDetailToDoForm.as_view()), name='todo_form'),
    url(r'^complete/$', ProjectDetailToDoCForm, name='todoc_form'),
)

Answer 1

只是一般性提示，因为您已发布所有代码，包括HTML / JS / Python / urls.py ......

如果 JS （客户端错误）中有错误，您将在浏览器日志（控制台）中看到它。
如果 urls.py 出现错误，您很可能会收到 HTTP响应404 Not Found ，这意味着该网址无法解析。
如果您收到 HTTP响应500内部服务器错误，这肯定意味着您遇到了服务器错误（python代码中的运行时错误 /views.py / 。< / LI>

一般情况下，请阅读最常见的回复代码及其含义HTTP/1.1: Status Code Definitions

Django - AJAX请求返回500内部服务器错误

1 个答案: