我希望在TABLE上显示数据库中的30行,但只显示已批准的条目。 这个“已批准的条目”是针对一行定义的,其值为“1表示已批准”,“0表示未批准”
这是我需要改变的代码:
<?php
$servername = "localhost";
$username = "username ";
$password = "password";
$dbname = "name";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, label, title_id, season, episode, approved FROM links order by id desc LIMIT 30 OFFSET 1";
$result = $last_id = $conn->query($sql);
if ($result->num_rows > 0)
{
echo "<table><tr><th>ID</th><th>Audio</th><th>URL</th><th>Temporada</th><th>Episodio</th><th>Aprobado</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>".$row["id"]."</td><td>".$row["label"]."</td>";
echo "<td><a href=";
if (empty($row['episode'])) {
echo '/peliculas-online/'.$row["title_id"];
}
else {
echo '/series-online/'.$row['title_id'].'/seasons/'.$row['season'].'/episodes/'.$row["episode"];
}
echo ">".$row["title_id"]."</a></td>";
echo "<td>".$row["season"]."</td><td>".$row["episode"]."</td><td>".$row["approved"]."</td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
就像你可以看到的,这个代码列表全部(已批准或未批准)...如何得到这样的东西:
如果行批准= 1显示行,否则隐藏(隐藏所有不仅仅是批准的行)
如果条目未获批准,则需要隐藏此表格行中的所有条目 - &gt; ID-标签的title_id季集的批准
由于
答案 0 :(得分:1)
您应该了解SELECT中的MySQL WHERE子句。
类似的东西:
"SELECT id, label, title_id, season, episode, approved
FROM links
WHERE approved = 1
ORDER BY id desc
LIMIT 30 OFFSET 1";
参考: