Question

我遇到了将表单数据保存回xml文件的问题，我最初从中导入了一些数据。

为简单起见，假设我有一个客户数据，名字和姓氏，我将其从文件导入datagridview。在这里，我有额外的表格文件放在我添加地址，电话号码和客户图片等详细信息。

一旦我添加了这些数据，我需要用xml中的这3个额外字段保存我的初始文件。如果需要，可以再次阅读。

我是新手并坚持如何做到这一点，请帮忙。感谢。

Answer 1

newel=xmlDoc.createElement("edition");
x=xmlDoc.getElementsByTagName("book")[0];
x.appendChild(newel);

您可以将新元素附加到XML DOM。以下是更多信息：http://www.w3schools.com/dom/dom_nodes_add.asp

Answer 2

由于您没有发布任何代码段，假设您没有任何结构，我已创建Employee类作为Data Model

//Data Model
class Employee
{
    string _firstName;
    string _lastName;
    string _address;
    string _phoneNumber;
    string _picturePath;

    public string FirstName { get; set; }
    public string LastName { get; set; }
    public string Address { get; set; }
    public string PhoneNumber { get; set; }
    public string PicturePath { get; set; }
}

private static void InitializeDataTableFromXML(ref DataTable dataTable)
{
        // you can read your new details from Contorls's value from your Form, then form a Enumerable collection like List<Employee> employees, and create a DataTable as folllows
        List<Employee> employees = new List<Employee>();

        // form your collection
        employees.Add(new Employee() { FirstName = "your First Name from XML File", LastName = "your Last Name from XML File or from Form Control", Address = "your new Address from Form Control or from Form Control", PhoneNumber = "your new Phone Number from Form Control", PicturePath = "your new Picture path from Form Control" });
        .
        .
        ,
        employees.Add(new Employee() { FirstName = "your First Name from XML File", LastName = "your Last Name from XML File or from Form Control", Address = "your new Address from Form Control or from Form Control", PhoneNumber = "your new Phone Number from Form Control", PicturePath = "your new Picture path from Form Control" });

        DataRow dataRow;
        foreach (var employee in employees)
        {
            dataRow = dataTable.NewRow();
            dataRow["FirstName"] = employee.FirstName;
            dataRow["LastName"] = employee.LastName;
            dataRow["Address"] = employee.Address;
            dataRow["PhoneNumber"] = employee.PhoneNumber;
            dataRow["PicturePath"] = employee.PicturePath;
            dataTable.Rows.Add(dataRow);
        }
}

private static void ReadOverriteXML(string xmlFilePath, DataTable dtNewXMLData)
{
        using (XmlWriter writer = XmlWriter.Create(xmlFilePath))
        {
            writer.WriteStartDocument();
            writer.WriteStartElement("Employees");

            foreach (DataRow row in dtNewXMLData.Rows)
            {
                writer.WriteStartElement("Employee");
                writer.WriteElementString("FirstName", row["FirstName"].ToString());
                writer.WriteElementString("LastName", row["LastName"].ToString());
                writer.WriteElementString("Address", row["Address"].ToString());
                writer.WriteElementString("PhoneNumber", row["PhoneNumber"].ToString());
                writer.WriteElementString("PicturePath", row["PicturePath"].ToString());
                writer.WriteEndElement();
            }

            writer.WriteEndElement();
            writer.WriteEndDocument();
        }
}    

// call to the methods
DataTable dtXML = GetDatTable();
InitializeDataTableFromXML(ref dtXML);
ReadOverriteXML("Employee.xml", dtXML);

将XML数据导入C＃Form＆amp; datagridview的

2 个答案: