Question

我有3个数组区域，min，max.If min和相应的max都是0然后我想把相应的区域变成数组。

region=["A","B","C","D","E","F","G"]
min= ["0","0","0","200","400","0","0"]
max= ["0","0","0","1000","1000","0","0"]

预期产出：

output=["A","B","C","F","G"]

在上面..ABCFG有相应的最小值和最大值都是0 ..所以我想要那些同时包含min和max 0的区域valuse..i.e区域

我在下面尝试但是没能继续下去

Hash[region.zip([min.map(&:to_i),max.map(&:to_i)].transpose)]

//output
{"A"=>[0, 0], "B"=>[0, 0], "C"=>[0, 0], "D"=>[200, 1000], "E"=>[400, 1000], "F"=>[0, 0], "H"=>[0, 0]}

Answer 1

这样做：

region.zip(min, max).select {|_, a, b| a == '0' && b == '0'}.map(&:first)

Answer 2

试试这个：

output = []
region.each_with_index { |r, i| output << r if min[i] == '0' && max[i] == '0' }
output # => ["A","B","C","F","G"]

Answer 3

另一种方式：

emin, emax = min.to_enum, max.to_enum

region.select do
  xmin = emin.next == '0'
  xmax = emax.next == '0'
  xmin && xmax
end
  # => ["A", "B", "C", "F", "G"]

额外信用：可以简化为：

region.select do
  emin.next == '0' && emax.next == '0'
end

如果值为零，则从哈希获取密钥

3 个答案: