我有从UIAlertController中调用的代码：
func createSomeFile() {
var output = (some NSData to output to file)
let fileName = NSTemporaryDirectory().stringByAppendingPathComponent("filename.ext")
let url: NSURL! = NSURL(fileURLWithPath: fileName)
var dataToWrite = output.dataUsingEncoding(NSUTF8StringEncoding)
dataToWrite?.writeToFile(url.absoluteString!, atomically: true)
documentController = UIDocumentInteractionController(URL: url)
documentController.UTI = "com.someUTI"
documentController.delegate = self
documentController.presentOpenInMenuFromRect(CGRectZero, inView: self, animated: true)
}
最后一行在Xcode中引发错误：“无法使用类型为...的参数列表调用'presentOpenInMenuFromRect'”
documentController被声明为类变量
var documentController = UIDocumentInteractionController()
请帮我解决这个问题。
答案 0 :(得分：0)
您无法将class Demo
{
private $runafterupdate;
...
public function up() {
Schema::connection('exitproducts')->create('exitcontrol_carmanager_manager', function($table)
{
$table->engine = 'InnoDB';
$table->increments('id');
$table->string('code');
$this->runafterupdate['code'] = true;
$table->timestamps();
});
}
if(isset($this->runafterupdate['code'])) {
echo "it worked!";
}
}
...
}
分配给应为self的参数（除非UIView是self的子类，但显然不是）
所以试试这个：
UIView