展平多维数组但维护密钥?

时间:2015-07-04 13:35:44

标签: php arrays

我有以下内容:

[6199]=>
  array(12) {
    ["Origin"]=>
    array(3) {
      ["name"]=>
      array(1) {
        [0]=>
        string(4) "Cuba"
      }
      ["slug"]=>
      array(1) {
        [0]=>
        string(27) "cuabn-havana-habanos-cigars"
      }
      ["id"]=>
      array(1) {
        [0]=>
        int(0)
      }
    }
    ["Filler"]=>
    array(3) {
      ["name"]=>
      array(2) {
        [0]=>
        string(9) "Dominican"
        [1]=>
        string(10) "Nicaraguan"
      }
      ["slug"]=>
      array(2) {
        [0]=>
        string(9) "dominican"
        [1]=>
        string(10) "nicaraguan"
      }
      ["id"]=>
      array(2) {
        [0]=>
        int(0)
        [1]=>
        int(1)
      }
    }
  }
  [6192]=>
  array(11) {
    ["Origin"]=>
    array(3) {
      ["name"]=>
      array(1) {
        [0]=>
        string(9) "Nicaragua"
      }
      ["slug"]=>
      array(1) {
        [0]=>
        string(27) "nicaraguan-new-world-cigars"
      }
      ["id"]=>
      array(1) {
        [0]=>
        int(0)
      }
    }
    ["Filler"]=>
      array(3) {
        ["name"]=>
        array(2) {
          [0]=>
          string(9) "Java"
          [1]=>
          string(10) "Nicaraguan"
        }
        ["slug"]=>
        array(2) {
          [0]=>
          string(9) "java"
          [1]=>
          string(10) "nicaraguan"
        }
        ["id"]=>
        array(2) {
          [0]=>
          int(0)
          [1]=>
          int(1)
        }
      }
  }

我的预期输出是:

  array(12) {
    ["Origin"]=>
    array(3) {
      ["name"]=>
      array(1) {
        [0]=>
        string(4) "Cuba".
        [1]=>
        string(9) "Nicaragua"
      }
      ["slug"]=>
      array(1) {
        [0]=>
        string(27) "cuabn-havana-habanos-cigars",
        [0]=>
        string(27) "nicaraguan-new-world-cigars"
      }
      ["id"]=>
      array(1) {
        [0]=>
        int(0)
      }
    }
    ["Filler"]=>
    array(3) {
      ["name"]=>
      array(2) {
        [0]=>
        string(9) "Dominican"
        [1]=>
        string(10) "Nicaraguan"
        [2]=>
        string(9) "Java"
      }
      ["slug"]=>
      array(2) {
        [0]=>
        string(9) "dominican"
        [1]=>
        string(10) "nicaraguan"
        [3]=>
        string(9) "java"
      }
      ["id"]=>
      array(2) {
        [0]=>
        int(0)
        [1]=>
        int(1)
      }
    }

了解它如何消除欺骗并合并每个维护“origin”键的数组。 我试过了:

  foreach ($resultterms as $keyname => $valuename){

    foreach ($valuename as $keysub => $valuesub) {

      foreach($valuesub['name'] as $keysubsub => $valuesubsub){

        # code...
        $prods_atts[$keysub]['name'][$keysubsub] = $valuesubsub;
        $prods_atts[$keysub]['slug'][$keysubsub] = $valuesub['slug'][$keysubsub];
        $prods_atts[$keysub]['id'][$keysubsub] = $valuesub['id'][$keysubsub];

      }
    }

  }

其中$resultterms是原始数组,但它不起作用。我想知道是否有一个很好的PHP函数我可以用它来合并这些而不是为每个循环嵌套这么多?

2 个答案:

答案 0 :(得分:2)

我相信你只是在寻找array_merge_recursive

call_user_func_array('array_merge_recursive', array_values($prod_atts));

为了试用它,您可以发布变量的var_export而不是var_dump吗?

echo(var_export($prod_atts, true));

答案 1 :(得分:1)

通过任何建议的方法合并您的数组。之后,您将获得重复的值。而且您只需要保存唯一的项目

$new = array_merge_recursive($resultterms['6199'], $resultterms['6192']);

foreach($new['Origin'] as &$item) { $item = array_unique($item); }
foreach($new['Filler'] as &$item) { $item = array_unique($item); }