Question

我有下面的html页面，当您在下拉列表中选择一个项目时，它会运行一个函数。每次我单步执行该功能，我都会到达

行

    $("#ddlRoute").html(procemessage).show();

我收到此错误：uncaught typeerror：$不是函数

你知道这是什么吗？我该如何解决这个问题？

    @using (Html.BeginForm())
    { 
            <div id="RowOne-form">
                    <div class="section1">
                        <h2>Select a Customer</h2>
                        <div>
                            <label for="Branch">Branch:</label>                
                            @Html.DropDownListFor(m => m.SelectedBranch, Model.BranchList, "Select Branch", new { @id = "ddlBranch", @style = "width:200px;", @onchange = "javascript:GetRoute(this.value);" })
                        </div>
                        <div>
                            <label>Route:</label>
                            <select id="ddlRoute" name="ddlRoute" style="width: 200px"></select>              
                        </div> 
                    </div>           
            <hr />
            <div class="form-Buttons-Sec" style="margin:35px;">
                <input id="Save1" type="button" value="Save"/>
                <input id="Cancel1" type="button" value="Cancel" />
            </div>

    }
    <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
    <script language="javascript" type="text/javascript">

        function GetRoute(_branchId) {
            var procemessage = "<option value='0'> Please wait...</option>";
            $("#ddlRoute").html(procemessage).show();
            var url = "/Home/GetRouteByBranchId/";

            $.ajax({
                url: url,
                data: { branchId: _branchId },
                cache: false,
                type: "POST",
                success: function (data) {
                    var markup = "<option value='0'>Select City</option>";
                    for (var x = 0; x < data.length; x++) {
                        markup += "<option value=" + data[x].Value + ">" + data[x].Text + "</option>";
                    }
                    $("#ddlRoute").html(markup).show();
                },
                error: function (reponse) {
                    alert("error : " + reponse);
                }
            });


        }
    </script>

Answer 1

看来你用来获取jQuery引用的url可能不正确。尝试使用这个......

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js"></script>

未捕获类型错误：$不是函数

1 个答案: