Question

以下代码（显然）有效：

(use [midje.sweet])

(with-state-changes [(before :contents (println "setup") :after (println "teardown"))]
  (fact "one" 
    (println "doing 1")
    1 => 1)
  (fact "two"
    (println "doing 2")
    (+ 1 1) => 2))

输出是预期的输出：

setup
doing 1
doing 2
teardown

但我希望将我的事实分组在一个单独的函数中：

(defn my-facts []
  (fact "one" ...)
  (fact "two" ...)
  #_( ... ))

(with-state-changes [(before :contents (println "setup") :after (println "teardown"))]
  (my-facts))

这次，midje无法执行代码，我收到以下错误：

Midje could not understand something you wrote: 
        Background prerequisites created by the wrapping version of
        `against-background` only affect nested facts. This one
        wraps no facts.

        Note: if you want to supply a background to all checks in a fact, 
        use the non-wrapping form. That is, instead of this:
            (fact 
              (against-background [(f 1) => 1] 
                (g 3 2 1) => 8 
                (h 1 2) => 7)) 
        ... use this:
            (fact 
              (g 3 2 1) => 8 
              (h 1 2) => 7 
              (against-background (f 1) => 1))

有没有办法实现我的目标？我想使用midje的设置和拆卸设施，但仍然可以将我的事实包含在单独的fn内。

Answer 1

我花了一些时间查看Midje源代码，我不认为这是可能的。 Midje在宏扩展期间严重依赖于解析和重写代码，并且当它获得单独函数调用的结果时，Midje宏（事实等）将已经被扩展和评估。如果你真的有决心，你可能会发生这种情况，但它必须使用一个宏来处理单独的事实，而不是函数，以便让Midje访问你的原始事实表格。 Midje几乎都是宏，因此很难与其他任何东西进行交互。

Midje的`with-state-changes`和函数调用

1 个答案: