MS Access中的InStr函数文本分隔符问题

Question

我的代码如下所示，它几乎是完美的，但它有一个小缺陷。

SELECT instr (1, "n123456 (name lastname)", "(")+1 AS [First Char], 
instr (1, "n123456 (name lastname)", ")")-1 AS [Last Char], 
mid("n123456 (name lastname)", instr (1, "n123456 (name lastname)",
"(")+1,instr (1, "n123456 (name lastname)", ")")) AS [text];

因此它返回以下值：

  

  
• [First Char] = 10
  
• [Last Char] = 22
  
• [text] =姓氏姓氏）
  

我无法弄清楚如何从字符串中删除最后一个括号。有什么想法吗？

Answer 1

mid函数语法是

Mid ( text, start_position, number_of_characters )

您指定的字符数是错误的。它应该是你的([LastChar]-1) - [First Char]

尝试以下代码

SELECT instr (1, "n123456 (name lastname)", "(")+1 AS [First Char], 
instr (1, "n123456 (name lastname)", ")")-1 AS [Last Char], 
mid("n123456 (name lastname)", instr (1, "n123456 (name lastname)", "(")+1,
instr (1, "n123456 (name lastname)", ")")-2 -
instr (1, "n123456 (name lastname)", "(")+1) AS [text];

o / p是