Question

我使用Spring来选择一个值。这是存储库中的查询：

@Query(value = "select * from incidents where descriptioninfo like %:descriptioninfo% and fixed = :fixed and starttimestamp > :startTime and deviceid in (select id from devices) and deviceid in (select deviceid from devicesmaps) and (incidentseverityid in (:incidentseverityid))  order by starttimestamp desc limit :start, :length", nativeQuery = true)
public List<IncidentEntity> getByStarttimestampAndDescriptioninfoAndSeverityAndFixed(@Param("startTime") String startTime, @Param("descriptioninfo") String descriptioninfo, @Param("incidentseverityid") List<Integer> incidentseverityid, @Param("start") int start, @Param("length") int length, @Param("fixed") int fixed);

如果我运行它，我会得到例外：

具有该名称[descriptioninfo]的参数不存在

奇怪的是，将选择更改为：

@Query(value = "select * from incidents where descriptioninfo like %:descriptioninfo% and fixed = :fixed and starttimestamp > :startTime and deviceid in (select id from devices) and deviceid in (select deviceid from devicesmaps) and (incidentseverityid = (:incidentseverityid))   order by starttimestamp desc limit :start, :length", nativeQuery = true)
public List<IncidentEntity> getByStarttimestampAndDescriptioninfoAndSeverityAndFixed(@Param("startTime") String startTime, @Param("descriptioninfo") String descriptioninfo, @Param("incidentseverityid") List<Integer> incidentseverityid, @Param("start") int start, @Param("length") int length, @Param("fixed") int fixed);

（仅从

更改

(incidentseverityid in (:incidentseverityid))

到

(incidentseverityid = (:incidentseverityid))

修复异常并检索所需的值！

可能的最小变化，从'in'到'='对不同的参数（'incidentseverityid'而不是'descriptioninfo'中的参数）修复了问题！

为什么？

带有'in'或'='的select在MySQL Workbench中使用相同的参数。
请不要告诉我改变：param to？1 because I had a problem with ? in java 8。
请注意，该表在MySQL中被转储和恢复甚至修复，其引擎在InnoDB和MyISAM之间进行了更改。
另请注意 - 即使创建一个名为“IncidentsServeritiesEntity”的类作为儿子并使用适当的int ID也无济于事 - 只能从'in'切换到'='。
```
@Param("incidentseverityid") List<IncidentsServeritiesEntity> incidentseverityid
```
如果我使用以下选项，则选择不起作用：
```
identseverityid in :incidentseverityid
```

或：

    (identseverityid in (:incidentseverityid))

（带括号）。

Answer 1

解决方案有点难看但有效：定义=而不是in缺少的内容，创建一个长or命令并传递它。

String allParams = "";

for (String currParam : param)
{
    allParams += ("param = " + currParam + " or "); 
}

allParams = allParams .substring(5, allParams .length() - 3);

使用'in'而不是'='的例外情况在Spring选择的地方

1 个答案: