1 + 1/2！ + 1/3！ +¼！ + ...... .....寻找总和

Question

Q值。 ）1 + 1/2！ + 1/3！ +¼！ + ...... .....
以下程序的输出始终为1.0。我是一个蟒蛇初学者。请告诉我有什么问题？请建议任何其他方法，以使该计划更好。 请不要使用内置功能。<​​/ strong>我想手动执行此操作。

    n=int(raw_input("Enter number of terms : ")) 

    d=0  #to sum all terms, initial value is 0

while n>0:
     j=n   #we start by taking factorial of the last term
     s=1   #to multiply to find factorial
     while j>0:
               s=s*j   #number gets multiplied to s and stored in s
               j=j-1   #number is decreased until it reaches 0
     n=n-1   #we will keep finding factorial until the very first term, i.e. 1 is reached
     x=float(1/s)   #to find reciprocal of the factorial we just found in     floating point
     d=d+x #adding to final sum

print "Sum of 1+1/2!+1/3!+1/4!+.... is ",d #printing

Answer 1

你需要在你的师的某个地方使用浮动。我只是让你＆＃34; s＆＃34;一个漂浮物。

n=int(raw_input("Enter number of terms : ")) 

d=0  #to sum all terms, initial value is 0

while n>0:
     j=n   #we start by taking factorial of the last term
     s=float(1)   #to multiply to find factorial
     while j>0:
               s=s*j   #number gets multiplied to s and stored in s
               j=j-1   #number is decreased until it reaches 0
     n=n-1   #we will keep finding factorial until the very first term, i.e. 1 is reached
     x=1/s   #to find reciprocal of the factorial we just found in     floating point
     d=d+x #adding to final sum

print "Sum of 1+1/2!+1/3!+1/4!+.... is ",d #printing