Question

我想迭代XML elemets按公共元素值对数据进行分组。输入XML结构是：

<?xml version="1.0" encoding="utf-8"?>
<Data>
<output outputType="CORRECTION">
    <row nodeName="ORDER_HEADER" tableName="ORDER_HEADER">
        <column columnName="ORDER_NUMBER">00001</column>
        <column columnName="Country">England</column>
        <column columnName="City">London</column>
    </row>
    <row nodeName="ORDER_HEADER" tableName="ORDER_HEADER">
        <column columnName="ORDER_NUMBER">00002</column>
        <column columnName="Country">England</column>
        <column columnName="City">Birmingham</column>
    </row>
    <row nodeName="ORDER_DETAIL" tableName="ORDER_DETAIL">
        <column columnName="ORDER_NUMBER">00001</column>
        <column columnName="Book">Gone with the wind</column>
        <column columnName="Qty">2</column>
    </row>
    <row nodeName="ORDER_DETAIL" tableName="ORDER_DETAIL">
        <column columnName="ORDER_NUMBER">00001</column>
        <column columnName="Book">Pride and Prejudice</column>
        <column columnName="Qty">3</column>
    </row>
    <row nodeName="ORDER_DETAIL" tableName="ORDER_DETAIL">
        <column columnName="ORDER_NUMBER">00002</column>
        <column columnName="Book">Jane Eyre</column>
        <column columnName="Qty">1</column>
    </row>
</output>
</Data>

我正在尝试创建以下输出：

<Transmission xmlns:xs="http://www.w3.org/2001/XMLSchema"
          xmlns="http://www.w3.org/1999/xhtml">
    <OrderNumber>00001</OrderNumber>
    <Country>England</Country>
    <City>London</CITY>
    <Book>Gone with the wind</Book>
    <QTY>2</QTY>
    <Book>Pride and Prejudice</Book>
    <QTY>3</QTY>
    <OrderNumber>00002</OrderNumber>
    <Country>England</Country>
    <City>Birmingham</CITY>
    <Book>Jane Eyre</Book>
    <QTY>1</QTY>
</Transmission>

这是我到目前为止的XSL：

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0"     xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/1999/xhtml">
<xsl:output method="xml"  indent="yes" omit-xml-declaration="yes"/>
<xsl:template match="/Data/output[@outputType='CORRECTION']">
    <Transmission>
        <xsl:for-each select="row[@tableName='ORDER_HEADER']">
            <OrderNumber>
                <xsl:value-of select="column[@columnName='ORDER_NUMBER']" />
            </OrderNumber>
            <Country>
                <xsl:value-of select="column[@columnName='Country']" />
            </Country>
            <City>
                <xsl:value-of select="column[@columnName='City']" />
            </City>
        </xsl:for-each>
    </Transmission>
</xsl:template>
</xsl:stylesheet>

我可以从每个订单标题输出详细信息，但无法查看如何选择和分组正确的订单详细信息。任何帮助将不胜感激。

由于

Answer 1

您可以使用密钥查找订单详细信息（适用于XSLT 1.0和XSLT 2.0）

<xsl:key name="detail" match="row[@nodeName='ORDER_DETAIL']" use="column[@columnName='ORDER_NUMBER']" />

然后，要获取给定订单号的订单详细信息，您可以使用如下键：

<xsl:for-each select="key('detail', column[@columnName='ORDER_NUMBER'])">

试试这个XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"  indent="yes" omit-xml-declaration="yes"/>
<xsl:key name="detail" match="row[@nodeName='ORDER_DETAIL']" use="column[@columnName='ORDER_NUMBER']" />
<xsl:template match="/Data/output[@outputType='CORRECTION']">
    <Transmission>
        <xsl:for-each select="row[@tableName='ORDER_HEADER']">
            <xsl:variable name="orderNumber" select="column[@columnName='ORDER_NUMBER']" />
            <OrderNumber>
                <xsl:value-of select="$orderNumber" />
            </OrderNumber>
            <Country>
                <xsl:value-of select="column[@columnName='Country']" />
            </Country>
            <City>
                <xsl:value-of select="column[@columnName='City']" />
            </City>
            <xsl:apply-templates select="key('detail', $orderNumber)" />
        </xsl:for-each>
    </Transmission>
</xsl:template>

<xsl:template match="row">
    <Book>
        <xsl:value-of select="column[@columnName='Book']" />
    </Book>
    <QTY>
        <xsl:value-of select="column[@columnName='Qty']" />
    </QTY>
</xsl:template>
</xsl:stylesheet>

注意，我转而使用xsl:apply-templates代替，只是为了减少过多的嵌套代码。我还使用了一个变量，以避免重复获取订单号。

顺便说一句，那真的是你想要的XML输出吗？将每个订单包装在包含父元素中可能更合乎逻辑，否则为订单提取书籍会变得更加困难。

<Transmission>
 <Order>
   <OrderNumber>00001</OrderNumber>
   <Country>England</Country>
   <City>London</City>
   <Book>Gone with the wind</Book>
   <QTY>2</QTY>
   <Book>Pride and Prejudice</Book>
   <QTY>3</QTY>
 </Order>
 <Order>
   <OrderNumber>00002</OrderNumber>
   <Country>England</Country>
   <City>Birmingham</City>
   <Book>Jane Eyre</Book>
   <QTY>1</QTY>
 </Order>
</Transmission>

使用XSLT 2.0基于元素值和属性对XML元素进行分组

1 个答案: