Question

我无法获取发送到pojo的json字符串。

com.fasterxml.jackson.databind.JsonMappingException：无法从START_ARRAY标记中反序列化com.sg.info.Account的实例在[来源：java.io.StringReader@1f6dcfe2; line：1，column：1]

这是json

[{"accno":9210255,"type":"Stock- and mutual funds account","default":true,"alias":"Karlsson Joachim"}]

解析

public void getAccounts()
    {
        ObjectMapper mapper = new ObjectMapper();
        String resp = Login.getBaseResource().path("accounts").request(Login.getResponsetype()).get(String.class);

        try  {

            account = mapper.readValue(resp, Account.class);

POJO

import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
import com.fasterxml.jackson.annotation.JsonInclude;
import com.fasterxml.jackson.annotation.JsonProperty;

@JsonInclude(JsonInclude.Include.NON_NULL)
@JsonIgnoreProperties(ignoreUnknown=true)
public class Account {

    public Account() {

    }
    private long accno;
    private String type;
    @JsonProperty("default")
    private String isDefault; 
    private String alias;


    public long getAccno() {
        return accno;
    }
    public void setAccno(long accno) {
        this.accno = accno;
    }
    public String getType() {
        return type;
    }
    public void setType(String type) {
        this.type = type;
    }
    public String getAlias() {
        return alias;
    }
    public void setAlias(String alias) {
        this.alias = alias;
    }
    @Override
    public String toString() {
        return "Account [accno=" + accno + ", type=" + type + ", alias="
                + alias + "]";
    }
    public String isDefault() {
        return isDefault;
    }
    @JsonProperty("default")
    public void setDefault(String isDefault) {
        this.isDefault = isDefault;
    }




}

Answer 1

您遇到的问题是您拥有的JSON是一个数组，并且可以拥有多个帐户。如果您将解析代码更改为类似的内容，它将起作用：

    ObjectMapper mapper = new ObjectMapper();
    String str = "[{\"accno\":9210255,\"type\":\"Stock- and mutual funds account\",\"default\":true,\"alias\":\"Karlsson Joachim\"}]";

    JavaType accountListType =  mapper.getTypeFactory().constructArrayType(Account.class);

    Account[] accounts = SharedJsonSerializer.objectMapper().readValue(str, accountListType);

当然最好使用集合类型，你可以使用mapper.getTypeFactory（）构建你想要的任何类型

将jsonnode转换为pojo

1 个答案: