Question

我正在尝试使用Python的Etree模块修改XML。我试图通过一个相当复杂的XML查找扫描项目＆＃39;。 ScanItem的子项有三个键（[＆＃39; name＆＃39;，＆＃39; type＆＃39;，＆＃39; value＆＃39;]）。我希望修改＆＃39; value＆＃39;的内容。

到目前为止，这是我的代码：

from lxml import etree

model_dir = 'D:\MPhil\Model_Building\Models\Retinoic_acid\[07]\Model_LIne_10'
model_name = 'M28.cps'
model_file=os.path.join(model_dir,model_name) #model_file contains the XML

IA=Identifiability_Analysis() # custom class
copasiML_str= IA.read_copasiML_as_string(model_file)
copasiML=etree.fromstring(copasiML_str) # parse XML with etree
parameters_dict=IA.extract_parameters_to_dict(model_file) #extract some parameters from the XML
reaction_name_i='v1'
parameter_name_i='Kcat'
maxi = float(parameters_dict[reaction_name_i][parameter_name_i])*2 #calculating changes
mini = float(parameters_dict[reaction_name_i][parameter_name_i])/2 # calculating changes

query = "//*[@name='ScanItem']"  #looks for the element called ScanItem
for j in copasiML_i.xpath(query):
    children = list(j) #gets the children of ScanItem
    for k in children:
        if k.attrib['name']=='Maximum': #finds the 'bit' that I want to change
            copasiML_i.set(k.attrib['value'],maxi) #an attempt at changing the value to maxi. This does not work

最后一行给出以下错误：

ValueError: Invalid attribute name u'0.0102086'  #which is the value of 'maxi'

有人知道我做错了什么吗？

由于

Answer 1

所以我最终弄明白了。它是一个简单的赋值，使用与普通Python字典相同的语法

使用Python的Etree设置XML的属性值

1 个答案: