Question

我使用swift编码图像

let base64String = data!.base64EncodedStringWithOptions(NSDataBase64EncodingOptions(rawValue: 0))

编码字符串的前222个字符是/9j/4AAQSkZJRgABAQAASABIAAD/4QBYRXhpZgAATU0AKgAAAAgAAgESAAMAAAABAAEAAIdpAAQAAAABAAAAJgAAAAAAA6ABAAMAAAABAAEAAKACAAQAAAABAAABLKADAAQAAAABAAABLAAAAAD/7QA4UGhvdG9zaG9wIDMuMAA4QklNBAQAAAAAAAA4QklNBCUAAAAAABDUHYzZjwCyBOmACZjs+EJ...

我用golang编码了相同的图像

sEnc := base64.StdEncoding.EncodeToString(imageData)

编码字符串的前224个字符是 /9j/2wCEAAgGBgcGBQgHBwcJCQgKDBQNDAsLDBkSEw8UHRofHh0aHBwgJC4nICIsIxwcKDcpLDAxNDQ0Hyc5PTgyPC4zNDIBCQkJDAsMGA0NGDIhHCEyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMv/AABEIASwBLAMBIgACEQEDEQH/xAGiAAABBQEBAQEB...

使用

在swift中解码图像时

let decodedData = NSData(base64EncodedString: base64String, options: NSDataBase64DecodingOptions(rawValue: 0))
var decodedimage = UIImage(data: decodedData!)

图像看起来完全一样。

当我在golang中使用

解码swift生成的base64字符串时

dec, err := base64.StdEncoding.DecodeString(imageData)

我在解码base64字符串时遇到错误：illegal base64 data at input byte 220这是+字符。但是当我解码golang生成的base64输出正确时。

为什么编码的字符串不同？我该如何解决？

编辑：

Swift最后10个字节eqvr h/9k=
Golang最后10个字节cvdR//2Q==

EDIT2：

在Golang中我使用ioutil for reading file

b, err := ioutil.ReadFile(fileName)

EDIT3：

为不同的测试用例添加了结果 https://www.dropbox.com/sh/zd1wj7ppjedrx6a/AAAoX15iztTimtav6U_8IF4Ma?dl=0

Answer 1

使用Swift编码的字符串，这显然是在Photoshop中生成的JPEG（JFIF是JPEG传输签名）：

$ echo '/9j/4AAQSkZJRgABAQAASABIAAD/4QBYRXhpZgAATU0AKgAAAAgAAgESAAMAAAABAAEAAIdpAAQAAAABAAAAJgAAAAAAA6ABAAMAAAABAAEAAKACAAQAAAABAAABLKADAAQAAAABAAABLAAAAAD/7QA4UGhvdG9zaG9wIDMuMAA4QklNBAQAAAAAAAA4QklNBCUAAAAAABDUHYzZjwCyBOmACZjs' | base64 -D | hexdump -C
00000000  ff d8 ff e0 00 10 4a 46  49 46 00 01 01 00 00 48  |......JFIF.....H|
00000010  00 48 00 00 ff e1 00 58  45 78 69 66 00 00 4d 4d  |.H.....XExif..MM|
00000020  00 2a 00 00 00 08 00 02  01 12 00 03 00 00 00 01  |.*..............|
00000030  00 01 00 00 87 69 00 04  00 00 00 01 00 00 00 26  |.....i.........&|
00000040  00 00 00 00 00 03 a0 01  00 03 00 00 00 01 00 01  |................|
00000050  00 00 a0 02 00 04 00 00  00 01 00 00 01 2c a0 03  |.............,..|
00000060  00 04 00 00 00 01 00 00  01 2c 00 00 00 00 ff ed  |.........,......|
00000070  00 38 50 68 6f 74 6f 73  68 6f 70 20 33 2e 30 00  |.8Photoshop 3.0.|
00000080  38 42 49 4d 04 04 00 00  00 00 00 00 38 42 49 4d  |8BIM........8BIM|
00000090  04 25 00 00 00 00 00 10  d4 1d 8c d9 8f 00 b2 04  |.%..............|
000000a0  e9 80 09 98 ec                                    |.....|
000000a5

使用Golang生成的字符串，无论如何：

$ echo '/9j/2wCEAAgGBgcGBQgHBwcJCQgKDBQNDAsLDBkSEw8UHRofHh0aHBwgJC4nICIsIxwcKDcpLDAxNDQ0Hyc5PTgyPC4zNDIBCQkJDAsMGA0NGDIhHCEyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMjIyMv/AABEIASwBLAMBIgACEQEDEQH/xAGiAAABBQEBAQEB' | base64 -D | hexdump -C
00000000  ff d8 ff db 00 84 00 08  06 06 07 06 05 08 07 07  |................|
00000010  07 09 09 08 0a 0c 14 0d  0c 0b 0b 0c 19 12 13 0f  |................|
00000020  14 1d 1a 1f 1e 1d 1a 1c  1c 20 24 2e 27 20 22 2c  |......... $.' ",|
00000030  23 1c 1c 28 37 29 2c 30  31 34 34 34 1f 27 39 3d  |#..(7),01444.'9=|
00000040  38 32 3c 2e 33 34 32 01  09 09 09 0c 0b 0c 18 0d  |82<.342.........|
00000050  0d 18 32 21 1c 21 32 32  32 32 32 32 32 32 32 32  |..2!.!2222222222|
00000060  32 32 32 32 32 32 32 32  32 32 32 32 32 32 32 32  |2222222222222222|
*
00000080  32 32 32 32 32 32 32 32  ff c0 00 11 08 01 2c 01  |22222222......,.|
00000090  2c 03 01 22 00 02 11 01  03 11 01 ff c4 01 a2 00  |,.."............|
000000a0  00 01 05 01 01 01 01 01                           |........|
000000a8

您需要发布完整的Go代码。看起来这就是错误的代码。那次运行的0x32非常可疑。

Swift和golang编码base64给出了不同的结果

1 个答案: