Question

我将如何解决这个问题？请不要介意数据注释的文本，这仅用于测试。我将如何删除数据注释？

   [SuppressMessage("Microsoft.Globalization", "CA1303:Do not pass literals as localized parameters",
        MessageId = "YouSource.DI.Web.Areas.HelpPage.TextSample.#ctor(System.String)",
        Justification = "End users may choose to merge this string with existing localized resources.")]
    [SuppressMessage("Microsoft.Naming", "CA2204:Literals should be spelled correctly",
        MessageId = "bsonspec",
        Justification = "Part of a URI.")]
    public int Get1Number([FromBody]string name)

我有这段代码

    public void RemovePublicModifier()
    {
        this.method = this.SanitizeString(this.method, Public);
    }
    public void RemoveDataAnnotation()
    {
        int startIndex = this.method.LastIndexOf(']');
        var result = this.method.Substring(startIndex + 1).Trim();

        this.method = result;
    }
    private string SanitizeString(string method, string filter)
    {
        var items = method.Split(' ').ToList();
        var publicItem = items.Where(i => i == filter).FirstOrDefault();
        if (publicItem != null)
        {
            items.Remove(publicItem);
        }
        var result = string.Join(" ", items.ToArray()).Trim();
        return result;
    }

但它给我一个错误的结果。

       string name)

我想要的是什么。

      int Get1Number([FromBody]string name)

Answer 1

string inputStr = @"[SuppressMessage(""Microsoft.Globalization"", ""CA1303:Do not pass literals as localized parameters"",
MessageId = ""YouSource.DI.Web.Areas.HelpPage.TextSample.#ctor(System.String)"",
Justification = ""End users may choose to merge this string with existing localized resources."")]
[SuppressMessage(""Microsoft.Naming"", ""CA2204:Literals should be spelled correctly"",
MessageId = ""bsonspec"",
Justification = ""Part of a URI."")]
public int Get1Number([FromBody]string name)";
Console.WriteLine(Regex.Replace(inputStr, @"(^|\s*)\[[\s\S]*?\]\s*public\s+", string.Empty));

public is also removed

Answer 2

您可以尝试执行此正则表达式替换：

(?ims)^\s*\[(?!\bpublic\b)[\s\S]*?\)\]\s*public\s*

替换为空字符串。

C＃：

var result = Regex.Replace(str, @"(?ims)^\s*\[(?!\bpublic\b)[\s\S]*?\)\]\s*public\s*", string.Empty);

这是demo

Answer 3

试试这个

Regex.Replace(inputStr, @"(?<!\()\[[^\]]+\]\r\n", string.Empty));

它与[]中的文字相匹配，但不会与(

前面的文字相匹配

Answer 4

尝试使用此正则表达式，它将消除抑制消息，也支持其他访问修饰符：

(\[[^]]+\)\])(?<modifiers>\s+\w+\s)?

如果您不想删除访问修饰符，则只需在Regex.Replace期间跳过此命名组。

Demo

Answer 5

以下代码会将<div style="top: calc(35%);"></div>提取到int Get1Number([FromBody]string name)变量。

text

如何使用正则表达式删除特定字符

5 个答案:

Demo