Question

我想每个月计算评估分数。评估范围从1-5。我想在表格中向他们展示每个评估每月评分的分数。这是数据。日期列的格式为：YYYY-MM-DD。

+-----------+---+---+---+---+---+
| date/eval | 5 | 4 | 3 | 2 | 1 |
+-----------+---+---+---+---+---+
|2015-06-01 | 10| 15| 2 | 3 | 0 |
+-----------+---+---+---+---+---+
|2015-06-02 | 20| 11| 5 | 4 | 1 |
+-----------+---+---+---+---+---+
|2015-06-03 | 5 | 10| 5 | 6 | 2 |
+-----------+---+---+---+---+---+
.
.
.
+-----------+---+---+---+---+---+
|2015-06-30 | 10| 15| 2 | 3 | 0 |
+-----------+---+---+---+---+---+

然后我需要在这样的表格中显示数据。

+------------+---+---+---+---+---+
| date/eval  | 5 | 4 | 3 | 2 | 1 |
+------------+---+---+---+---+---+
|june 2015   |110|105| 32| 23| 0 |
+------------+---+---+---+---+---+
|july 2015   |132| 50| 21| 13| 0 |
+------------+---+---+---+---+---+
|august 2015 |151| 55| 42| 30| 0 |
+------------+---+---+---+---+---+

我能想到的所有sql脚本都是group by。但它只适用于按日期分组。

这是脚本：

select * from evaluation group by year,month(datetime) asc

如何计算每次评估的唯一值。

Answer 1

创建数据结构并填写测试数据：

CREATE TABLE evaluation (
  evaldate date NOT NULL,
  grade1 int(11) NOT NULL,
  grade2 int(11) NOT NULL,
  grade3 int(11) NOT NULL,
  grade4 int(11) NOT NULL,
  grade5 int(11) NOT NULL,
  PRIMARY KEY (evaldate)
);

INSERT INTO evaluation VALUES('2015-07-14', 1, 2, 3, 4, 5);
INSERT INTO evaluation VALUES('2015-07-15', 2, 2, 2, 2, 2);
INSERT INTO evaluation VALUES('2015-08-12', 5, 4, 3, 2, 1);
INSERT INTO evaluation VALUES('2015-08-13', 1, 1, 1, 1, 1);

执行您要执行的查询：

SELECT year(evaldate)
     , month(evaldate)
     , sum(grade1)
     , sum(grade2)
     , sum(grade3)
     , sum(grade4)
     , sum(grade5) 
  FROM evaluation 
 group 
    by year(evaldate)
     , month(evaldate);

返回：

year(evaldate) month(evaldate) sum(grade1) sum(grade2) sum(grade3) sum(grade4) sum(grade5)
2015           7               3           4           5           6           7
2015           8               6           5           4           3           2

在我看来，这就像你要找的结果一样，对吗？

如何按日期和行值计算值组

1 个答案: