Question

我试图用新主义制作这个模型现在正在运作，但我无法弄清楚如何使返回类型更短或更清晰。必须有办法做到这一点： []struct { UserId string "json:\"account.UserId\""; FirstName string "json:\"account.firstName\""; LastName string "json:\"account.lastName\"" }

分为： []Account或其他什么

package models

import (
  "errors"
  "strconv"
  "time"
  // "fmt"

  "github.com/jmcvetta/neoism"
)

var (
  Accounts map[string]*Account
)

var (
  db *neoism.Database
)

func panicErr(err error) {
  if err != nil {
    panic(err)
  }
}

type Account struct {
  UserId   string `json:"account.UserId"`
  FirstName     string `json:"account.firstName"`
  LastName      string `json:"account.lastName"`
}

func init() {
  var err error
  db, err = neoism.Connect("http://neo4j:password@localhost:7474/db/data")
  if err != nil {
    panic(err)
  }
}

// map[lastName:PATRUS UserId:7f7014f9-bd59-4739-8e1b-5aebfa00f4c5 firstName:LARISSA]

func GetAccounts() []struct { UserId string "json:\"account.UserId\""; FirstName string "json:\"account.firstName\""; LastName string "json:\"account.lastName\"" } {
  stmt := `
    MATCH (account:Account) RETURN account.UserId, account.firstName, account.lastName
  `

  res := []struct {
    UserId string `json:"account.UserId"`
    FirstName  string `json:"account.firstName"`
    LastName  string `json:"account.lastName"`
  }{}

  // construct query
  cq := neoism.CypherQuery{
    Statement:  stmt,
    Result:     &res,
  }

  // execute query
  err := db.Cypher(&cq)
  panicErr(err)

  return res
}

这是另一个副本： http://play.golang.org/p/14gzc0a_89

我是新手，我将从这些新例子的例子出发： https://gist.github.com/verdverm/b43444063995a7f5b913

有很多例子，但是verdverm总是只输出而不是返回。

我还有一个控制器，我想输出json。

package controllers

import (
  "github.com/astaxie/beego"
  "social/models"
)

type AccountsController struct {
  beego.Controller
}

func (c *AccountsController) Get() {
  c.Data["json"] = models.GetAccounts()
  // c.Data["json"] = "hello world"
  c.ServeJson()
}

感谢有关新手的任何帮助/提示！

Answer 1

package models

import (
  "errors"
  "strconv"
  "time"
  // "fmt"

  "github.com/jmcvetta/neoism"
)

var (
  Accounts map[string]*Account
)

var (
  db *neoism.Database
)

func panicErr(err error) {
  if err != nil {
    panic(err)
  }
}

type Account struct {
  UserId   string `json:"account.UserId"`
  FirstName     string `json:"account.firstName"`
  LastName      string `json:"account.lastName"`
}

func init() {
  var err error
  db, err = neoism.Connect("http://neo4j:password@localhost:7474/db/data")
  if err != nil {
    panic(err)
  }
}

// map[lastName:PATRUS UserId:7f7014f9-bd59-4739-8e1b-5aebfa00f4c5 firstName:LARISSA]

func GetAccounts() []Account {
  stmt := `
    MATCH (account:Account) RETURN account.UserId, account.firstName, account.lastName
  `

  var accounts []Account

  // construct query
  cq := neoism.CypherQuery{
    Statement:  stmt,
    Result:     &accounts,
  }

  // execute query
  err := db.Cypher(&cq)
  panicErr(err)

  return accounts
}

需要在函数上方使用Account结构，然后在里面创建一个变量，并使用指向var的新事件db的响应。

我怎样才能清理这种新生代的回归类型？

1 个答案: