我用于表单验证的Javascript代码无法正常工作

时间:2015-07-16 23:59:09

标签: javascript

我创建了简单的表单验证,但没有任何工作。下面是我的表单和javascript的代码。我从教科书中把它拿走了。我有一个提交按钮。当我点击它没有任何反应。我正在使用外部.js文件,并确实包含页面上的部分链接。我非常感谢您的意见。

<form name="reservation" onsubmit="return validate(this);">
<fieldset>
<legend>Reservation</legend>
<br/>
<label>Name*</label>
<br/>
<input type="text" name="txtName" id="txtName" size="60">
<br/><br/>
<label>Date and Time*</label>
<br/>
<input type="text" id="txtDate" name="txtDate" size="40"><a href="javascript:NewCal('txtDate','mmmddyyyy',true,12)"><img src="../Images/cal.gif" width="18" height="18" border="0" alt="Pick a date"></a>
<br/><br/>
<label>Party Size*</label>
<br/>
<input type="text" id="txtParty" name="txtParty" size="20">
<br/><br/>
<label>Phone*</label>
<br/>
<input type="text" id="txtPhone" name="txtPhone" size="40">
<br/><br/>
<label>Email*</label>
<br/>
<input type="text" id="txtEmail" name="txtEmail" size="60">
<br/><br/>
<input type="submit" id="button" value="Submit"/>
<p id="main_text">
*=required
</p>
</fieldset>
</form>

使用Javascript:

function validate(form){

    var returnValue=true;

    var name = form.txtName.value;
    var date = form.txtDate.value;
    var party = form.txtParty.value;
    var phone = form.txtPhone.value;
    var email = form.txtEmail.value;


        if (name=="") {
        returnValue = false;
        alert("Name is a required field");
        document.reservation.txtName.focus();
    }


    if (date=="") {
        returnValue = false;
        alert("Date is a required field");
        reservation.txtName.focus();
    }

    if (party=="") {
        returnValue = false;
        alert("Party Size is a required field");
        document.reservation.txtName.focus();
    }

    if (phone=="") {
        returnValue = false;
        alert("Phone is a required field");
        document.reservation.txtName.focus();
    }

    if (email=="") {
        returnValue = false;
        alert("Email is a required field");
        document.reservation.txtName.focus();
    }
    alert("Thank for providing your information.\n
    We will get back you as soon as possible.");
    return returnValue;
}

1 个答案:

答案 0 :(得分:-2)

我认为你应该考虑使用jQuery它更加有效和易于使用!您还应该考虑使用else if()语句。

var name = $('#txtName').val(); 
var email = $('#txtEmail').val();
    if(name == ""){ alert("Please fill in the name field"); 
        $('#txtName').focus(); 
        return false;
     }
     else if(email == ""){ alert("Please fill in the email field");
     $('#txtName').focus(); 
     return false;
     }else{ 
      alert("All good");
      return true;
    }
相关问题