会话未保存为id

时间:2015-07-19 14:31:43

标签: php mysql

基本上我用我的PHP代码解决了一个未知问题。

CODE(login_config.php):

    <?php   
session_start();                    //POST VARIABLES
                        $submit = $_POST['login_submit'];
                        $password = $_POST['login_password'];
                        $email = $_POST['login_email'];



if(isset($submit)){
   require 'password_config.php';
   require 'connect.php';

//PASSWORD VERIFYING
   $pass_query = "SELECT password FROM users WHERE email='$email'";
   $queried = mysql_query($pass_query);
   while($row = mysql_fetch_array($queried)){
   $user_pass = $row['password'];
   $veri_password = password_verify($password, $user_pass);
   }
   if($veri_password != true){$errors[] = '-Account does not exist ';}
   elseif($veri_password = true){

//CHECKING NUM ROWS
   $sql = "SELECT id, username FROM users WHERE email='$email'";
   $entered_user = mysql_query($sql);
   $num_rows = mysql_num_rows($entered_user);
   //STORING ID AS SESSION
   while($row1 = mysql_fetch_array($entered_user)){
   //PROBLEM IS HERE 
   $row1['id'] = $id;
   }

//ERRS ARRAY ESTABLISHED
   $errors = array();

//FURTHER VERIFYING
   if( empty($password) || empty($email) )
   {
   $errors[] = 'Please do not leave fields empty';
   }
   elseif( $num_rows != 1 )
   {
   $errors[] = '-Account does not exist ';
   }
   elseif( $num_rows == 1 )
   {
   $id = $_SESSION['key'];

      header('Location: profile.php');
      exit();
      }
   }

   }
?>

问题:为什么当我通过header()重定向到profile.php时,$ _SESSION [&#39; key&#39;]值为空?我一直在使用var_dump()来证明这一点。我希望我的会话密钥在我的数据库中具有用户ID的值,我发现我的代码没有问题。

3 个答案:

答案 0 :(得分:1)

首先,$id变量未定义

执行$row1['id'] = $id;表示assigning $id value to $row1['id'] 如果您想在$id中存储用户ID,那么您应该使用

$id = $row1['id'];

$id = $_SESSION['key'];相同的错误这意味着assiging $_SESSION['key'] to $id。如果要在会话中存储$id值:

$_SESSION['key'] = $id;

答案 1 :(得分:0)

我可以看到你的代码中有2个问题,你们都在运行循环来获取数据所以这里是代码,我标记了你正在做的行吗

<?php   
session_start(); 
//POST VARIABLES
$submit = $_POST['login_submit'];
$password = $_POST['login_password'];
$email = $_POST['login_email'];

if(isset($submit)){
   require 'password_config.php';
   require 'connect.php';

//PASSWORD VERIFYING
   $pass_query = "SELECT password FROM users WHERE email='$email'";
   $queried = mysql_query($pass_query);
   //while($row = mysql_fetch_array($queried)){ //no need to run loop here
   $row = mysql_fetch_array($queried);
   $user_pass = $row['password'];
   $veri_password = password_verify($password, $user_pass);
  // } //remove this too
   if($veri_password != true){$errors[] = '-Account does not exist ';}
   elseif($veri_password = true){

//CHECKING NUM ROWS
   $sql = "SELECT id, username FROM users WHERE email='$email'";
   $entered_user = mysql_query($sql);
   $num_rows = mysql_num_rows($entered_user);
   //STORING ID AS SESSION
   //while($row1 = mysql_fetch_array($entered_user)){//no need to run loop here
   $row1 = mysql_fetch_array($entered_user);
   //PROBLEM IS HERE
   //$row1['id'] = $id; // you can't store values in $id like this
   $id = $row1['id']; // right way to do
   } //remove this too

//ERRS ARRAY ESTABLISHED
   $errors = array();

//FURTHER VERIFYING
   if( empty($password) || empty($email) )
   {
   $errors[] = 'Please do not leave fields empty';
   }
   elseif( $num_rows != 1 )
   {
   $errors[] = '-Account does not exist ';
   }
   elseif( $num_rows == 1 )
   {
   $id = $_SESSION['key']; //again wrong you cant load $id into session
   $_SESSION['key'] = $id; //right way to load $id variable value into session

      header('Location: profile.php');
      exit();
      }
   }

   }
?>

答案 2 :(得分:0)

始终包含

ini_set("display_errors", "On");
ERROR_REPORTING(E_ALL);

作为测试时代码中的前两行,或相应地更改测试环境php.ini。 这将为您提供来自php的所有可能的帮助/错误声明

其次,在打开Php-tag之前删除任何空格 使用session_start()时; 如果有空格,正如您的代码所示,php会表现不正常。

然后再看一下你的代码。 / niels ml