Question

我目前正在创建一个演示注册系统（我会注意到这不是作业或作业）我希望如果用户已购买该项目，则禁用“添加到购物车”（并且之前的项目，它反映在数据库中

    //current URL of the Page. cart_update.php redirects back to this URL
$current_url = base64_encode($url="http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']);

//Query to get item information
$results = $mysqli->query("SELECT * FROM events ORDER BY eventid");// WHERE sort = '$sort' 
$remaining = $mysqli->query("SELECT * FROM orders");
$obj_r = $remaining->fetch_object(); // obj_r means objects remaining

//Query to disable already purchaced items
$QgetSignups = $mysqli->query("SELECT s.eventid, o.status FROM signups s JOIN orders o ON s.orderid = o.orderid WHERE s.userid = $userid AND o.status = 1");            
$signedup = array();

    while($row = mysqli_fetch_assoc($QgetSignups))
    //while($row = $QgetSignups->fetch_array(MYSQLI_NUM))
{
    array_push($signedup,$row["eventid"]);
}

if ($results) { 

    //fetch results set as object and output HTML
    while($obj = $results->fetch_object())
    {
        echo '<div class="product">'; 
        echo '<form method="post" action="cart_update.php">';
        echo '<div class="product-thumb"><img src="images/'.$obj->image.'"></div>';
        echo '<div class="product-content"><h4>'.$obj->name.'</h4>';
        echo '<div class="product-desc">'.$obj->description.'</div>';
        echo '<div class="product-info">';
        echo 'Price: '.$currency.$obj->price.' | ';
        echo 'Items Left: '.$obj->max.' | ';
        echo '<input type="hidden" style="width:20px;height:15px;" type="text" name="product_qty" value="1" size="3" />'; // OLD CODE TO DISPLAY QTY BOX: Qty: <input style="width:20px;height:15px;" type="text" name="product_qty" value="1" size="3" />';

        if($signupAmount[$row['eventid']] >= $row['max'])
        {
            echo '<button class="add_to_cart">Add To Cart</button>';
        }

        if(in_array($row['eventid'],$signedup))
        {
            print_r($signedup);
            //echo '<button DISABLED class="add_to_cart">Add To Cart</button>';
        }
        echo '</div></div>';
        echo '<input type="hidden" name="product_code" value="'.$obj->name.'" />';
        echo '<input type="hidden" name="type" value="add" />';
        echo '<input type="hidden" name="return_url" value="'.$current_url.'" />';
        echo '</form>';
        echo '</div>';
    }

}


?>

脚本当前尝试检查所购买的商品是否与“eventid”匹配（即代表商品编号的数字）。到目前为止，我试图通过将项目编号推入数组，然后使用in_array来检查它，但是如果我使用方法while($row = mysqli_fetch_assoc($QgetSignups))，则in_array不起作用（它拉动了数组编号，但是in_array没有正确检查它是否存在），如果我使用//while($row = $QgetSignups->fetch_array(MYSQLI_NUM))，则array_push不会收集值，但是in_array方法会尝试显示数组（尽管它是空的）。

Answer 1

您没有在当前while循环中迭代$ row，其中存在以下代码。

if (in_array($row['eventid'], $signedup)) {
    print_r($signedup);
    //echo '<button DISABLED class="add_to_cart">Add To Cart</button>';
}

我不确定您的数据库架构是如何设置的，但可能应该如下：

if (in_array($obj->eventid, $signedup)) {
    print_r($signedup);
    //echo '<button DISABLED class="add_to_cart">Add To Cart</button>';
}

MySQLI：in_array没有正常工作

1 个答案: