问题

由用户启动的特定Flow的进程必须在执行芹菜作业之前在队列中等待。每个用户都有这些进程的队列。根据计划或手动触发，允许队列中的下一个进程继续。

实施例

我的流中的节点进入命名队列。应用程序中的其他逻辑为每个队列确定何时允许下一个任务继续进行。选择队列中的下一个任务并调用其激活的done（）方法。

示例流程可能如下所示：

class MyFlow(Flow):

    start = flow.Start(...).Next(queue_wait)
    queue_wait = QueueWait("myQueue").Next(job)
    job = celery.Job(...).Next(end)
    end = flow.End()

问题

实施排队的最佳方法是什么？在上面的例子中，我不知道＆＃34; QueueWait＆＃34;应该是。

我已经阅读了文档和视图流代码，但是我还不清楚是否可以使用内置的Node和Activation类（如func.Function）或者如果我这样做需要使用自定义类扩展。

Answer 1

经过多次实验，我找到了一个可行且简单的解决方案：

from viewflow.flow import base
from viewflow.flow.func import FuncActivation
from viewflow.activation import STATUS


class Queue(base.NextNodeMixin,
            base.UndoViewMixin,
            base.CancelViewMixin,
            base.DetailsViewMixin,
            base.Event):

    """
    Node that halts the flow and waits in a queue. To process the next waiting task
    call the dequeue method, optionally specifying the task owner.

    Example placing a job in a queue::

        class MyFlow(Flow):
            wait = Queue().Next(this.job)
            job = celery.Job(send_stuff).Next(this.end)
            end = flow.End()

        somewhere in the application code:
        MyFlow.wait.dequeue()
        or:
        MyFlow.wait.dequeue(process__myprocess__owner=user)

    Queues are logically separated by the task_type, so new queues defined in a
    subclass by overriding task_type attribute.
    """

    task_type = 'QUEUE'
    activation_cls = FuncActivation

    def __init__(self, **kwargs):
        super(Queue, self).__init__(**kwargs)

    def dequeue(self, **kwargs):
        """
        Process the next task in the queue by created date/time. kwargs is
        used to add task filter arguments, thereby effectively splitting the queue
        into subqueues. This could be used to implement per-user queues.

        Returns True if task was found and dequeued, False otherwise
        """
        filter_kwargs = {'flow_task_type': self.task_type, 'status': STATUS.NEW}
        if kwargs is not None:
            filter_kwargs.update(kwargs)

        task = self.flow_cls.task_cls.objects.filter(**filter_kwargs).order_by('created').first()
        if task is not None:
            lock = self.flow_cls.lock_impl(self.flow_cls.instance)
            with lock(self.flow_cls, task.process_id):
                task = self.flow_cls.task_cls._default_manager.get(pk=task.pk)
                activation = self.activation_cls()
                activation.initialize(self, task)
                activation.prepare()
                activation.done()
            return True

        return False

我尝试使其尽可能通用，并支持多个命名队列的定义以及子队列，例如每用户队列。

viewflow.io：实现队列任务

问题

实施例

问题

1 个答案: