Question

我们试图在按钮点击时调用一个函数，但由于某种原因，该按钮不会调用该函数。谁能告诉我们为什么？

<body>

<button onclick="instagramclick()">Login to instagram</button>
<button onclick="myFunction()">Test Button</button>

<script>
function myFunction() {
    alert("Hello World");
}

function instagramclick(){
    alert("button clicked");
    window.location.href = "https://instagram.com/oauth/authorize/?client_id=8a612cd650344523808233c0468c80ed&redirect_uri=http://u-ahmed.github.io/HookedUp/&response_type=token";
    var token = window.location.href.substring(43);

    if(token="s_denied&error_reason=user_denied&error_description=The+user+denied+your+request"){
    alert("That's fine, but we can't access your instagram without your permission.");
    }
    else {
    jQuery(function($) {

        function writeToFile(token){
            var fso = new ActiveXObject("Scripting.FileSystemObject");
            var fh = fso.OpenTextFile("D:\\instagramtoken.txt");
            fh.WriteLine(", ,"+ token);
            fh.Close();
        }
    });

}
</script>

</body>

Answer 1

试试这会对你有所帮助。函数中存在语法错误。

<body>

  <button onclick="instagramclick()">Login to instagram</button>
  <button onclick="myFunction()">Test Button</button>

  <script>
    function myFunction() {
      alert("Hello World");
    }

    function instagramclick() {
      alert("button clicked");
      window.location.href = "https://instagram.com/oauth/authorize/?client_id=8a612cd650344523808233c0468c80ed&redirect_uri=http://u-ahmed.github.io/HookedUp/&response_type=token";
      var token = window.location.href.substring(43);

      if (token = "s_denied&error_reason=user_denied&error_description=The+user+denied+your+request") {
        alert("That's fine, but we can't access your instagram without your permission.");
      } else {
        jQuery(function($) {

          function writeToFile(token) {
            var fso = new ActiveXObject("Scripting.FileSystemObject");
            var fh = fso.OpenTextFile("D:\\instagramtoken.txt");
            fh.WriteLine(", ," + token);
            fh.Close();
          }
        });

      }
    }
  </script>

</body>

Answer 2

instagramclick functionn的关闭括号缺少这就是为什么点击事件没有解雇

Answer 3

您缺少instagramclick（）函数上的紧密括号。

按钮没有调用功能

3 个答案: