Question

花点时间看看这两个简单的类：

use ValueObjects\Address;

class Person {

    private $address;

    public function setAddress(Address $address){
        $this->address = $address;
    }
}

class Address {
    private $line1 = "";
    private $line2 = "";
    private $city = "";
    private $state = "";
    private $zip = "";

    public function __construct($line1, $line2, $city, $state, $zip){
        $this->line1 = $line1;
        $this->line2 = $line2;
        $this->city = $city;
        $this->state = $state;
        $this->zip = $zip;
    }

    public function getLine1(){ ... }
    public function getLine2(){ ... }
    // ...
}

这是我正在尝试做的事情：

// I have the class instance
$person = new Person();  

// I have the setter method name "setAddress"
$setter = "set".ucfirst("address");

// I have these parameters
$line1 = "123 Main St.";  
$line2 = "";
$city = "New York";
$state = "NY";
$zip = "10000";

// I only have the information you see above, how do I use that to set
// these values into $person? 
?????

我想我需要使用某种形式的反射？（另外，我听说Reflection可能性能很慢，所以如果你知道的话，可以随意推荐任何更好的方法。）

Answer 1

我只想更改构造函数以接受键值数组。类似的东西：

public function __construct($array){
 foreach ( $array as $key => $value ) {
    $this->$key = $value;
  }
}

然后，不要设置变量，在数组中设置键。如

$data = array( 
'line1' => "123 Main St.",
'line2' => "",
'city' => "New York",
'state' => "NY",
'zip' => "10000",
);

我倾向于只实现松散类型的函数，而不是使用大量的反射。例如：

<?php

class Person {

    private $address;

    public function setAddress(Address $address){
        $this->address = $address;
    }

    // loosely typed setter
    public function _setAddress($data){
        $this->address = new Address($data);
    }
}

class Address {

    private $line1 = "";
    private $line2 = "";
    private $city = "";
    private $state = "";
    private $zip = "";

    public function __construct($array){
     foreach ( $array as $key => $value ) {
        $this->$key = $value;
      }
    }
}

$p = new Person();

$setter = "_setAddress";
$data = array(
    'line1' => "123 Main St.",
    'line2' => "",
    'city' => "New York",
    'state' => "NY",
    'zip' => "10000",
);

$p->$setter($data);

print_r($p);

否则，如果你使用反射（可能会更慢），那就是：

How do I get the type of constructor parameter via reflection?

Answer 2

我确定最好的解决方案是避免反射，而是构建某种自动映射器。你可以看到Jimmy Bogard完成了something like this in .net。 PHP没有指定的返回类型，但我认为我以某种方式解决了这个问题。

（PHP Reflection？）创建一个类型提示的新实例，作为参数

2 个答案: