Question

我的查询存在SUM和GROUP_CONCAT功能问题。

总和值会随着GROUP_CONCAT值的增加而变化。

以下是我的代码：

SELECT     ul.display_name, 
           ul.photo, 
           ul.user_id, 
           Sum(ulr.level_score)              AS level_scores, 
           Sum(ulr.level_timer)              AS level_timer, 
           Group_concat(ulr.level_completed) AS levels, 
           Group_concat(DISTINCT c.bit_id)   AS bit_id 
FROM       user_level_responses              AS ulr 
INNER JOIN user_login                        AS ul 
ON         ( 
                      ul.user_id=ulr.user_id) 
INNER JOIN c_member AS cm 
ON         ( 
                      cm.user_id=ul.user_id 
           AND        cm.user_approval='Y' 
           AND        cm.delete_status='0' 
           AND        cm.status='1') 
INNER JOIN ctree ct 
ON         ( 
                      cm.circuit_id=ct.circuit_id ) 
INNER JOIN cir AS c 
ON         ( 
                      c.circuits_id=cm.circuit_id 
           AND        c.builtin=0 
           AND        c.delete_status='0' 
           AND        c.status='1') 
WHERE      Match(ct.circuit_path) against ('_902_') 
AND        ulr.institution_id=321 
AND        ulr.delete_status=0 
AND        ulr.status=1 
AND        ul.delete_status=0 
GROUP BY   ulr.user_id 
ORDER BY   level_scores DESC, 
           level_timer ASC, 
           ul.display_name limit 500

如果实际得分为900，如果我在GROUP_CONCAT中有2个ID，那么实际得分是原来得分的两倍。

Expected OUTPUT:

user1   2010.cs,btech   960 00:01:08    Completed
user2   btech   920 00:01:08    Completed

OUTPUT GETTING:

user1   2010.cs,btech   1920    00:01:08    Completed
user2   btech   920 00:01:08    Completed

实际金额的两倍，即960。

Answer 1

您的问题是您的多个ID会在分组之前将结果的行加倍。您可以通过加入子查询中的所有外部数据来解决此问题。

我完全不知道您的数据库的结构，也不知道所有的功能，但这是在重新组织您的查询时陷入困境。如果你需要，我可以写一个更简单的SQLFiddle来向你展示我的意思。

SELECT     ul2.display_name, 
           ul2.photo, 
           ul2.user_id, 
           Sum(ulr.level_score)              AS level_scores, 
           Sum(ulr.level_timer)              AS level_timer, 
           Group_concat(ulr.level_completed) AS levels, 
           ul2.bit_id
FROM       user_level_responses              AS ulr
INNER JOIN (
    SELECT
    ul.display_name,
    ul.photo,
    ul.user_id,
    GROUP_CONTACT(DISTINCT c.bit_id)  as bit_id
    FROM       user_login                        AS ul 
    INNER JOIN c_member AS cm 
    ON         ( 
                  cm.user_id=ul.user_id 
           AND        cm.user_approval='Y' 
           AND        cm.delete_status='0' 
           AND        cm.status='1') 
    INNER JOIN ctree ct 
    ON         ( 
                  cm.circuit_id=ct.circuit_id ) 
    INNER JOIN cir AS c 
    ON         ( 
                  c.circuits_id=cm.circuit_id 
           AND        c.builtin=0 
           AND        c.delete_status='0' 
           AND        c.status='1') 
    WHERE      Match(ct.circuit_path) against ('_902_') 
    AND        ul.delete_status=0
    GROUP BY   ul.user_id
) AS ul2
ON  (
        ulr.user_id = ul2.user_id )
WHERE      ulr.institution_id=321 
AND        ulr.delete_status=0 
AND        ulr.status=1 
GROUP BY   ulr.user_id
ORDER BY   level_scores DESC, 
           level_timer ASC, 
           ul.display_name limit 500

查询中的Mysql SUM和GROUP_CONCAT问题

1 个答案: