取项数取决于具体的计算方法

Question

我有一张这样的表：

我有这样的查询：

SELECT T_BOE_Stock_Detail.itemCode,
       T_Master_Item.itemName AS Description,
       T_Master_Item.categoryCode AS Category,
       sum(T_BOE_Stock_Detail.qty - T_BOE_Stock_Detail.ReservedQty) AS Qty
FROM T_BOE_Stock_Detail
LEFT OUTER JOIN T_Master_Item ON T_BOE_Stock_Detail.itemCode = T_Master_Item.itemCode
GROUP BY T_BOE_Stock_Detail.itemCode,
         T_Master_Item.itemName,
         T_Master_Item.categoryCode
HAVING sum(T_BOE_Stock_Detail.qty - T_BOE_Stock_Detail.ReservedQty) > 0
ORDER BY T_Master_Item.categoryCode,
         T_BOE_Stock_Detail.itemCode

在查询中我得出这样的内容：

itemcode   description   category     qty
076-00002  bottom                       2

在同一查询中我想再添加两列第1列是goodcount 2是defectcount ..
在doctype列中，我们有好的和有缺陷的项目。所以我想添加计数。

my expected out put like this:
 itemcode   description   category     qty  good   defective
  076-00002  bottom                    2       1      1

我怎么能做到这一点？

Answer 1

您可以在传递给case的表达式中使用sum。所以你可以这样做：

sum(case when DOCTYPE = 'GOOD' then 1 else 0 end)

Answer 2

我更新了ans，但由于没有测试数据我无法测试，你可以试试吗

 Select T.itemCode,T.Description,T.Category,
 SUM(CASE WHEN DOCTYPE = 'GOOD' THEN 1 ELSE 0 END) Good,
 SUM(CASE WHEN DOCTYPE = 'DEFECTIVE' THEN 1 ELSE 0 END) Defective  
 from 
 (SELECT T_BOE_Stock_Detail.itemCode, T_Master_Item.itemName as Description,
       T_Master_Item.categoryCode as Category, 
 SUM(T_BOE_Stock_Detail.qty - T_BOE_Stock_Detail.ReservedQty) As Qty,
 FROM T_BOE_Stock_Detail 
 LEFT OUTER JOIN T_Master_Item ON T_BOE_Stock_Detail.itemCode = T_Master_Item.itemCode
 GROUP BY T_BOE_Stock_Detail.itemCode, T_Master_Item.itemName,T_Master_Item.categoryCode
 HAVING SUM(T_BOE_Stock_Detail.qty - T_BOE_Stock_Detail.ReservedQty) > 0 
 ORDER BY T_Master_Item.categoryCode, T_BOE_Stock_Detail.itemCode
 ) T
 inner join T_BOE_Stock_Detail ON T_BOE_Stock_Detail.itemCode = T.itemCode
 GROUP BY T.itemCode, T.Description,T.Category

Answer 3

试试这个

select t_boe_stock_detail.itemcode, t_master_item.itemname as description,
t_master_item.categorycode as category, 
sum(t_boe_stock_detail.qty - t_boe_stock_detail.reservedqty) as qty,
sum(case when doctype = 'good' then 1 end) as good,
sum(case when doctype = 'defective' then 1 end) as defective 
from t_boe_stock_detail 
left outer join t_master_item on t_boe_stock_detail.itemcode = t_master_item.itemcode
group by t_boe_stock_detail.itemcode, t_master_item.itemname,t_master_item.categorycode
having sum(t_boe_stock_detail.qty - t_boe_stock_detail.reservedqty) > 0 
order by t_master_item.categorycode, t_boe_stock_detail.itemcode

Answer 4

这是完整的脚本，在计算之前通过聚合改善了性能：

SELECT BOE.itemCode,
       M.itemName AS Description,
       M.categoryCode AS Category,
       sum(BOE.qty) - sum(BOE.ReservedQty) AS Qty,
       count(case when DOCTYPE = 'GOOD' then 1 end) good,
       count(case when DOCTYPE = 'DEFECTIVE' then 1 end) defective
FROM T_BOE_Stock_Detail BOE
LEFT OUTER JOIN
  T_Master_Item M
ON BOE.itemCode = M.itemCode
GROUP BY BOE.itemCode,
         M.itemName,
         M.categoryCode
HAVING sum(BOE.qty) > sum(BOE.ReservedQty)
ORDER BY M.categoryCode,
         BOE.itemCode

不知道如何在DOCTYPE前加上，你应该在我的例子中使用M或BOE