使用Retrofit将动态JSON解析为POJO

时间:2015-08-06 10:13:29

标签: android json gson retrofit

嗨我有json,它有一些动态字段名称:

{
"status": {
    "rcode": 200,
    "message": "OK"
},
"data": {
    "0": {
        "SubFranchiseID": "0",
        "OutletID": "607",
        "OutletName": "Spill "
    },
    "1": {
        "SubFranchiseID": "0",
        "OutletID": "32",
        "OutletName": "PizzaRoma"
    }
},
"hash": "b262c62ea3c8c693ad35210289a487d6963434d7"

}

“0”和“1”是动态字符串值。

从这里How to parse Dynamic lists with Gson annotations?

我创建了我的Data类:

public class Data {

   public Map<String, Restaurant> restaurants = new HashMap<>();;

   public Map<String, Restaurant> getRestaurants() {
      return restaurants;
   }
}

但是当我在Retrofit中使用getRestaurants()。size()时,我得到零值。

应该如何更改我的数据类?

编辑:

我的主要课程:

public class MyClass{

private Status status;
private Data data;
private String hash;

public Data getData() {
    return data;
}
// other getter and setters
}

Retrofit和RxJava:

RetrofitService service1 = ServiceFactory.createRetrofitService(RetrofitService.class, RetrofitService.API_ENDPOINT);
    service1.data()
            .subscribeOn(Schedulers.newThread())
            .observeOn(AndroidSchedulers.mainThread())
            .subscribe(new Subscriber<MyClass>() {

                @Override
                public final void onNext(MyClass response) {

                    if(response.getData().getRestaurants().size() == 0)
                        Log.d("1", "size is ZERO ");

                }
            });

2 个答案:

答案 0 :(得分:2)

解决方案是不使用Data类,而是将MyClass更改为:

public class MyClass{

private Status status;

@SerializedName("data")
private Map<String, Restaurant> data;

private String hash;

public Map<String, Restaurant> getData() {
    return data;
}
// other getter and setters
}

答案 1 :(得分:0)

以下两个课程应该适合你。

class Data {
    Map<String, List<Outlet>> types;
}

class Outlet {
String SubFranchiseID;
String OutletID;
String OutletName;
}
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