Question

我试图制作一个添加行的发票系统，从教程和数据中正确插入tbl_orderdetail，但我无法将数据插入tbl_order。

这是2个MYSQL表：

CREATE TABLE IF NOT EXISTS `tbl_order` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`re_name` varchar(255) DEFAULT NULL,
`locat⁮ion` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

CREATE TABLE IF NOT EXISTS `tbl_orderdetail` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`order_id` int(11) DEFAULT NULL,
`product_name` varchar(255) DEFAULT NULL,
`quantity` varchar(255) DEFAULT NULL,
`price` varchar(255) DEFAULT NULL,
`discount` int(11) DEFAULT NULL,
`amount` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=73 ;

这是我的连接代码：

<?php
$cn = mysql_connect('localhost','root','');
if($cn)
{
mysql_select_db('mydb',$cn);
}

if(isset($_POST['submit']))
$re_name = $_POST['re_name'];
$location = $_POST['location'];
{
mysql_query ("INSERT INTO tbl_order(re_name,location)        VALUES('{$_POST['re_name']}','{$_POST['location']}')");
$id = mysql_insert_id();
for($i = 0 ;$i < count($_POST['productname']);$i++)
{
    mysql_query("INSERT INTO tbl_orderdetail 
                SET order_id        = '{$id}', 
                    product_name    = '{$_POST['productname'][$i]}', 
                    quantity        = '{$_POST['quantity'][$i]}', 
                    price           = '{$_POST['price'][$i]}', 
                    discount        = '{$_POST['discount'][$i]}', 
                    amount          = '{$_POST['amount'][$i]}'
                ");
}
}
?>

我的代码有什么问题？

以下是提交值的表单：

<form  action="" method="post"> 
<div class="box-body">
            <div class="form-group">
                ReceptName
                <input type="text" name="re_name" id="re_name" class="form-control">
            </div>
            <div class="form-group">
                Location
                <input type="text" name="location" id="location" class="form-control">
            </div>
            <input type="submit" class="btn btn-primary" name="submit" id="submit" value="Save Record">
    </div>

        <table class="table table-bordered table-hover">
            <thead>
                <th>No</th>
                <th>ProductName</th>
                <th>Quantity</th>
                <th>Price</th>
                <th>Discount</th>
                <th>Amount</th>
                <th><input type="button" value="+" id="add" class="btn btn-primary"></th>
            </thead>
            <tbody class="detail">
                <tr>
                    <td class="no">1</td>
                    <td><input type="text" class="form-control productname" name="productname[]"></td>
                    <td><input type="text" class="form-control quantity" name="quantity[]"></td>
                    <td><input type="text" class="form-control price" name="price[]"></td>
                    <td><input type="text" class="form-control discount" name="discount[]"></td>
                    <td><input type="text" class="form-control amount" name="amount[]"></td>
                    <td><a href="#" class="remove">Delete</td>
                </tr>
            </tbody>

            <tfoot>
                <th></th>
                <th></th>
                <th></th>
                <th></th>
                <th></th>
                <th style="text-align:center;" class="total">0</th>
            </tfoot>
        </table>
    </div>      
          </div><!-- /.box -->
          </form> 
        </div><!--/.col (left) -->

Answer 1

谢谢大家的帮助。我删掉了tbl_order并创建了一个名为'orcamen'的新文件。

这是有效的PHP代码：

if(isset($_POST['submit']))
{
$razao     = $_POST["razao"];
$local      = $_POST["local"];
$condicao     = $_POST["condicao"];
$estado         = $_POST["estado"];
$material       = $_POST["material"];
$obs        = $_POST["obs"];
mysql_query
("INSERT INTO orcamen ( id , razao , local , condicao , estado , material , obs ) 
        VALUES ( NULL , '$razao', '$local', '$condicao', '$estado', $material', '$obs')");
$id = mysql_insert_id();
for($i = 0 ;$i < count($_POST['productname']);$i++)
{
    mysql_query("INSERT INTO tbl_orderdetail 
                SET order_id        = '{$id}', 
                    product_name    = '{$_POST['productname'][$i]}', 
                    quantity        = '{$_POST['quantity'][$i]}', 
                    price           = '{$_POST['price'][$i]}', 
                    discount        = '{$_POST['discount'][$i]}', 
                    amount          = '{$_POST['amount'][$i]}'
                ");
}
}

PHP - 1表，2表 - 无法将数据插入表1

1 个答案: