Question

我的问题是：我有一个用户ID：0001 和到期代码：2015-10-10 12:00

我需要的是加密这两个值，以便我可以有一些像： TRE-3DR-SER-WER-67J-AX3（类似这样），也可以解密为原始值。

我所做的是混淆两个值，删除空格和破折号，并创建一个等同于单个字符的字母或数字。

我的问题是我希望生成的kay更安全，更难解码，如果可能的话更短的字符串。

Answer 1

您应该保持激活密钥独立，与失效日期和用户ID无关。它实际上创建了一种解密自己密钥的方法。代替;让你的桌子类似于下面的。

+----------------------------------------+
|   UserID    |    Key    |    Expiry    |
+----------------------------------------+

您可以生成ID：

<?php
function sernum()
{
    $template   = 'XX99-XX99-99XX-99XX-XXXX-99XX';
    $k = strlen($template);
    $sernum = '';
    for ($i=0; $i<$k; $i++)
    {
        switch($template[$i])
        {
            case 'X': $sernum .= chr(rand(65,90)); break;
            case '9': $sernum .= rand(0,9); break;
            case '-': $sernum .= '-';  break; 
        }
    }
    return $sernum;
}


// try it, lets generate 4 serial numbers
echo '<pre>';

for ($i=0; $i < 4; $i++) echo sernum(), '<br/>';

echo '</pre>';
?>

<强>输出：

WS41-IZ91-55XO-23WA-WVZS-20VK

SJ42-CV50-79DA-55UV-TERR-28IJ

LY80-CN84-69LV-73EW-ZZEU-09AI

IS86-RG15-39CG-38HK-XLUG-86FO

然后检查生成的密钥是否正在使用（1 / 1,000,000几率〜）

Answer 2

Encoding:

 $user = "0001"; //Solution only works if this value is always 4 characters.
 $datetime = "2015-10-10 12:00";

 $reps = array("-", " ", ":");
 $unencoded = $user . str_replace($reps, "", $datetime);
 //gives: 001201510101200

 $encoded = strtoupper(base64_encode($unencoded)); 

 //This will always be 20 characters long
 //Result: MDAXMJA5OTK5OTAXMJAW

 $finalCode = substr($encoded, 0, 5) . "-"
              .substr($encoded, 4, 5) . "-"
              .substr($encoded, 9, 5) . "-"
              .substr($encoded, 14, 5) . "-"

 //result: MDAXM-JA5OT-K5OTA-XMJAW

Decode:

 $input = "MDAXM-JA5OT-K5OTA-XMJAW";

 $encoded = str_replace("-", "", $input );
 $decoded = base64_decode($encoded);

 $year = substr($decoded, 4, 4);
 $month = substr($decoded, 8, 2);
 $day = substr($decoded, 10, 2);
 $hour = substr($decoded, 12, 2);
 $min = substr($decoded, 14, 2);

 $userid = substr($decoded, 0, 4);
 $date = new DateTime($year . "-". $month . "-" .$day. " ".$hour.":".$min);

Note: I would not recommend doing this, it is very insecure. I would follow the advice of some of the other answers and keep your code random and seperate to the user ID and date/time.

如何生成激活密钥（或串行密钥）

2 个答案: