Question

这是我的代码

executeProgram:
    for (int i= 0; 1< memory.length; i++)
    {   
        String twoDigitMemory = String.format("%02d",memory[i] );
        System.out.print(twoDigitMemory +" ? +");
        accumulator = input.nextInt();

        if (input.nextInt() == -99999)
        {
            System.out.println("*** Program loading completed ***");
            System.out.println("*** Program execution begins  ***");
            break executeProgram;
        }
    }

这是我的输出。我输入123。

***            Welcome to Simpletron!            ***
*** Please enter your program one instruction    ***
*** (or data word) at a time. I will display     ***
*** the location number and a question mark (?)  ***
*** You then type the word for that location.    ***
*** Type -99999 to stop entering your program    ***
00 ? +123

输入123并按Enter键后，我希望for循环再次运行打印“00？+”但没有任何反应，输入会保存到变量

Answer 1

您希望用户输入两次号码。一旦你在accumulater中存储，而另一个只是为了比较不需要的if (input.nextInt() == -99999)这样的数字。相反，您应该使用accumulater变量进行检查，如：

if (accumulater == -99999)

为什么我的循环只运行一次？

1 个答案: