Question

我想做一个多选一个依赖另一个。当我选择水果然后它显示三个选项香蕉橙aple然后选择banbana它显示另一个选项红橙黄色。但问题显示红色orege黄色所以第三类型我面临问题

<html>
<head>

</head>
</body>

<select name="select1" id="select1">
<option value="1">Fruit</option>
<option value="2">Animal</option>
<option value="3">Bird</option>
<option value="4">Car</option>
</select>

<select name="select2" id="select2">
<option value=""></option>
<option value="1">Banana</option>
<option value="1">Apple</option>
<option value="1">Orange</option>
<option value="2">Wolf</option>
<option value="2">Fox</option>
<option value="2">Bear</option>
<option value="3">Eagle</option>
<option value="3">Hawk</option>
<option value="4">BWM<option>
</select>
 // here is my problem
<select name="select3" id="select3">
<option value=""></option>
<option value="1">red</option>
<option value="1">orange</option>
<option value="1">yellow</option>
<option value="2">white</option>
<option value="2">gray</option>
<option value="2">blue</option>
<option value="3">ash</option>
<option value="3">silver</option>
<option value="4">gold<option>
</select>
<script type="text/javascript" src="js/jquery-1.7.2.min.js"></script>
<script type="text/javascript" src="js/function.js"></script>

        <script type="text/javascript">
$("#select1").change(function() { 
if($(this).data('options') == undefined){
    /*Taking an array of all options-2 and kind of embedding it on the select1*/
    $(this).data('options',$('#select2 option').clone());
    } 
var id = $(this).val();
var options = $(this).data('options').filter('[value=' + id + ']');
$('#select2').html(options);
});

$("#select2").change(function() { 
if($(this).data('options') == undefined){
    /*Taking an array of all options-2 and kind of embedding it on the select1*/
    $(this).data('options',$('#select3 option').clone());
    } 
var id = $(this).val();
var options = $(this).data('options').filter('[value=' + id + ']');
$('#select3').html(options);
});

</script>
</body>
</html>

Answer 1

$("#select1").change(function() {
  if ($(this).data('options') == undefined) {
    /*Taking an array of all options-2 and kind of embedding it on the select1*/
    $(this).data('options', $('#select2 option').clone());
  }
  var id = $(this).val();
  var options = $(this).data('options').filter('[value=' + id + ']');
  $('#select2').html(options);
});

$("#select2").change(function() {
  if ($(this).data('options') == undefined) {
    /*Taking an array of all options-2 and kind of embedding it on the select1*/
    $(this).data('options', $('#select3 option').clone());
  }
  var id = $(this).val();
  var options = $(this).data('options').filter('[value1=' + id + ']');
  $('#select3').html(options);
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select name="select1" id="select1">
<option value="1">Fruit</option>
<option value="2">Animal</option>
<option value="3">Bird</option>
<option value="4">Car</option>
</select>

<select name="select2" id="select2">
<option value1 = "1" value=""></option>
<option value1 = "1" value="1">Banana</option>
<option value1 = "1" value="1">Apple</option>
<option value1 = "2" value="1">Orange</option>
<option value1 = "2" value="2">Wolf</option>
<option value1 = "2" value="2">Fox</option>
<option value1 = "3" value="2">Bear</option>
<option value1 = "3" value="3">Eagle</option>
<option value1 = "4" value="3">Hawk</option>
<option value1 = "4" value="4">BWM<option>
</select>

<select name="select3" id="select3">
<option value1 = "1" value=""></option>
<option value1 = "1" value="1">red</option>
<option value1 = "1" value="1">orange</option>
<option value1 = "2" value="1">yellow</option>
<option value1 = "2" value="2">white</option>
<option value1 = "2" value="2">gray</option>
<option value1 = "3" value="2">blue</option>
<option value1 = "3" value="3">ash</option>
<option value1 = "4" value="3">silver</option>
<option value1 = "4" value="4">gold<option>
</select>

多选择选项彼此依赖

1 个答案: