Question

我的Android应用程序在套接字关闭之前不会收到数据（通常我强行关闭服务器，然后响应进入客户端）。

任何关心的人都会看到一些代码：

-Server

private void receiveCallback(IAsyncResult ar)
    {
        Socket socket = (Socket)ar.AsyncState;
        int received = socket.EndReceive(ar);
        byte[] dataBuf = new byte[received];
        Array.Copy(_buffer, dataBuf, received);
        string text = Encoding.ASCII.GetString(dataBuf);

        form.logMessage("Recieved: " + text);
        //Check commands
        if (!String.IsNullOrWhiteSpace(text))
        {
            sendText(form.onCommand(text), socket);
        }
        socket.BeginReceive(_buffer, 0, _buffer.Length, SocketFlags.None, new AsyncCallback(ReceiveCallback), socket);

    }

    public void sendText(string message,Socket socket)
    {
        byte[] data = Encoding.ASCII.GetBytes(message);
        form.logMessage("Sending: " + message);
        socket.NoDelay = true;
        socket.BeginSend(data, 0, data.Length, SocketFlags.None, new AsyncCallback(sendCallback), socket);
        form.logMessage("Sent!");
        socket.NoDelay = false;

    }

- 客户端

sendButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            Log.i(TAG, "Clicked send button!");
            String babam =  ((EditText)findViewById(R.id.requestText)).getText().toString();
            Log.i(TAG,"Going to send: " + babam);

                new Thread(new ResponseThread(babam)).start();


        }
    });
public class ResponseThread implements Runnable{

    String toSend;

    public ResponseThread(String toSend)
    {
        this.toSend = toSend;

    }


    @Override
    public void run() {

        try {
            PrintStream stream = new PrintStream(socket.getOutputStream(),true);
            stream.println(toSend);
            Log.i(TAG, "Sent request!");
            Log.i(TAG, "Waiting for reponse...");



            BufferedReader in = new BufferedReader(new InputStreamReader(socket.getInputStream()));
            String response = in.readLine();

            Log.i(TAG,"Response: " + response);
            statusText.setText(response);
        } catch (IOException e) {
            e.printStackTrace();
        }

    }
}

这是我的一些输出：

-Server

[8/9/2015 9:04:28 PM] Recieved: roll
[8/9/2015 9:04:28 PM] Rolled dice! 6 + 4 = 10
[8/9/2015 9:04:28 PM] Sending: Rolled!
[8/9/2015 9:04:28 PM] Sent!
[8/9/2015 9:04:28 PM] Recieved: 

[8/9/2015 9:04:29 PM] Recieved: roll
[8/9/2015 9:04:29 PM] Rolled dice! 5 + 1 = 6
[8/9/2015 9:04:29 PM] Sending: Rolled!
[8/9/2015 9:04:29 PM] Sent!
[8/9/2015 9:04:29 PM] Recieved:

- 客户端

08-09 20:48:29.133  12801-12801/com.artish1.sockettest I/Client﹕ Clicked send  button!
08-09 20:48:29.133  12801-12801/com.artish1.sockettest I/Client﹕ Going to send: roll
08-09 20:48:29.158  12801-13029/com.artish1.sockettest I/Client﹕ Sent request!
08-09 20:48:29.158  12801-13029/com.artish1.sockettest I/Client﹕ Waiting for reponse...
08-09 20:49:04.371  12801-12801/com.artish1.sockettest I/Client﹕ Clicked send button!
08-09 20:49:04.371  12801-12801/com.artish1.sockettest I/Client﹕ Going to send: roll
08-09 20:49:04.382  12801-13280/com.artish1.sockettest I/Client﹕ Sent request!
08-09 20:49:04.382  12801-13280/com.artish1.sockettest I/Client﹕ Waiting for reponse...
08-09 20:49:37.399  12801-13029/com.artish1.sockettest I/Client﹕ Response: Rolled!YepRolled!Yep
08-09 20:49:37.400  12801-13280/com.artish1.sockettest I/Client﹕ Response: null

请注意所有响应是如何同时出现的，那就是我强行关闭服务器的时候。

我对套接字没有经验，但我一直在查看有关此问题的其他帖子，有人说要强制刷新请求。这样我可以在客户端上获取它，但我已经通过服务器发送它（通过输出获得确认）。

有人想带一只雄鹅吗？

Answer 1

尝试在邮件末尾添加\n。也不要将“NoDelay”设置为false。你正在进行异步发送。

Java android客户端套接字在套接字断开后才得到响应

1 个答案: