Question

我想包含每个加载的绝对路径，因为我已经重写了url并且想要确保populateResults.php加载

$(document).ready(function() {
  $("#results").load("functions/populateResults.php");  //initial page number to load
  $(".pagination").bootpag({
     total: <?php echo $pages; ?>,
     page: 1,
     maxVisible: 5
  }).on("page", function(e, num){
    e.preventDefault();
    window.scrollTo(0, 0);

    $("#results").prepend('<div class="loading-indication"><img src="/content/ajax-loader.gif" /> &nbsp; Please wait... Loading New Courses...</div>');
    $("#results").load("functions/populateResults.php", {'page':num});
  });

});

</script>

我不确定并且不认为做/ functions / populateResult会起作用。

更新

<?php $root_url = $_SERVER['HTTP_HOST']; ?>

<script>

var root_url = '<?= $root_url ?>';

$(document).ready(function() {
  $("#results").load(root_url + "/functions/populateResults.php");  //initial page number to load
  $(".pagination").bootpag({
     total: <?php echo $pages; ?>,
     page: 1,
     maxVisible: 5
  }).on("page", function(e, num){
    e.preventDefault();
    window.scrollTo(0, 0);

    $("#results").prepend('<div class="loading-indication"><img src="/content/ajax-loader.gif" /> &nbsp; Please wait... Loading New Courses...</div>');
    $("#results").load(root_url + "/functions/populateResults.php", {'page':num});
  });

});

</script>

Answer 1

这就是我要做的：使用PHP获取根URL，将其设置为变量并将其发送给JS，以便在您希望的地方使用它。

<?php
$base_url = $_SERVER['HTTP_HOST'];
?>
<script>
    var base_url = '<?= $base_url ?>';

    $(document).ready(function () {
        $("#results").load(base_url + "/functions/populateResults.php");
        //.. your other code..
    });

</script>

从绝对路径AJAX加载

1 个答案: