Question

CREATE TABLE IF NOT EXISTS `live_product` (
`id` int(11) unsigned NOT NULL,
  `product_details` text NOT NULL,
  `price` decimal(10,2) NOT NULL,
  `tag1` varchar(255) NOT NULL,
  `tag2` varchar(255) NOT NULL
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ;

INSERT INTO `live_product` (`id`, `product_details`, `price`,   `tag1`, `tag2`) VALUES
(1, 'Product 1', '302.54', 'man,boy,girl', '22'),
(2, 'Product 2', '457.00', 'man,girl', '22'),
(3, 'Product 3', '157.00', 'girl', '24'),
(4, 'Product 4', '1157.00','man,boy,girl', '22'),
(5, 'Product 5', '957.00', 'man,boy,girl', '22'),
(6, 'Product 6', '757.00', 'boy,girl', '22'),
(7, 'Product 7', '157.00', 'boy', '24');

高级搜索的2个mysql查询需要2个结果

+------+-------------+
| Tag1 | Total_Count |
+------+-------------+
| girl |           6 |
| man  |           4 |
+------+-------------+

此结果需要

+----+-----------------+---------+--------------+------+
| id | product_details | price   | tag1         | tag2 |
+----+-----------------+---------+--------------+------+
|  1 | Product 1       |  302.54 | man,boy,girl | 22   |
|  2 | Product 2       |  457.00 | man,girl     | 22   |
|  3 | Product 3       |  157.00 | girl         | 24   |
|  4 | Product 4       | 1157.00 | man,boy,girl | 22   |
|  5 | Product 5       |  957.00 | man,boy,girl | 22   |
|  6 | Product 6       |  757.00 | boy, girl    | 22   |
+----+-----------------+---------+--------------+------+

SELECT t.tag1 as Tag1, count(*) AS Total_Count FROM
    (SELECT
      live_product.id,
      SUBSTRING_INDEX(SUBSTRING_INDEX(live_product.tag1, ',', numbers.n), ',', -1) tag1
    FROM
      (SELECT 1 n UNION ALL SELECT 2
       UNION ALL SELECT 3 UNION ALL SELECT 4) numbers INNER JOIN live_product
      ON CHAR_LENGTH(live_product.tag1)
         -CHAR_LENGTH(REPLACE(live_product.tag1, ',', ''))>=numbers.n-1
    ORDER BY
      id, n) t
    GROUP BY t.tag1
    ORDER BY Total_Count DESC, t.tag1 ASC;

以上查询仅提供逗号分隔计数，但当我在价格之间添加更多条件时，它会给出错误的结果。

Answer 1

尝试一下，如果它适合你 -

SELECT b.sub AS Tag1, COUNT(a.id) AS Total_Count FROM 
live_product a 
JOIN 
(
SELECT SUBSTRING_INDEX(tag1,',',1) sub FROM live_product UNION 
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(tag1,',',2),',',-1) sub FROM live_product UNION 
SELECT SUBSTRING_INDEX(tag1,',',-1) FROM live_product sub
) b ON FIND_IN_SET(b.sub,a.tag1) 
GROUP BY b.sub;

从具有特定条件的单列计算逗号分隔值

1 个答案: