Question

我的编码时间不长（不到3周），我想测试并尝试基于文本的游戏。我可能做得很差，但在面对决定时我试图在第一个决定中嵌套另一个决定。但是当我尝试做出决策1的选项B时，它会尝试运行一个嵌套在决策1的选项A下的决定，这会导致问题。我会告诉你我的意思：

kill1 = input("Attack old man? (y/n) ")
if kill1 == "y":
print("You strike the old man with all your force")
time.sleep(1)
print("Old Man staggers back, his right arm crippled")
else:
print("Thanks for the staff")

if kill1 == "y":
kill2 = input("Strike again or run away? (s/r) ")
if kill2 == "s":
print("You swing the staff into the mans ribs")
time.sleep(1)
print("The man falls to the ground, incapacitiated")
else:
print("You run away into the woods")

输出/错误：

Attack old man? (y/n) n
Thanks for the staff  
Traceback (most recent call last):
  File "/Users/alex/Desktop/game.py", line 28, in <module>
    if kill2 == "s":
NameError: name 'kill2' is not defined

很抱歉，如果格式不正确，我很安静，文字选项会让我感到困惑。

Answer 1

问题在于：

if kill1 == "y":
    kill2 = input("Strike again or run away? (s/r) ")
if kill2 == "s":
    print("You swing the staff into the mans ribs")

如果kill1不是"y"，则永远不会为变量kill2分配值。

看起来您应该缩进代码，以便if kill2 == "s"块位于if kill1 == "y"块内，如下所示：

if kill1 == "y":
    kill2 = input("Strike again or run away? (s/r) ")
    if kill2 == "s":
        print("You swing the staff into the mans ribs")

停止变量播放的问题

1 个答案: