Question

假设我有这个数组

[0,0] = A
[0,1] = B
[0,2] = C
[1,0] = D
[1,1] = E
[1,2] = F
[2,0] = G
[2,1] = H
[2,2] = I
[3,0] = J
[3,1] = K
[3,2] = L

我希望将它们写在这样的文本文件中：

A B C
D E F
G H I
J K L

我该怎么做？

Answer 1

Jagged 数组通常比 2D 数组更方便。

public static class ArrayExtensions {
  // In order to convert any 2d array to jagged one
  // let's use a generic implementation
  public static T[][] ToJagged<T>(this T[,] value) {
    if (Object.ReferenceEquals(null, value))
      return null;

    // Jagged array creation
    T[][] result = new T[value.GetLength(0)][];

    for (int i = 0; i < value.GetLength(0); ++i) 
      result[i] = new T[value.GetLength(1)];

    // Jagged array filling
    for (int i = 0; i < value.GetLength(0); ++i)
      for (int j = 0; j < value.GetLength(1); ++j)
        result[i][j] = value[i, j];

    return result;
  }
}

因此，在您的情况下，您可以将 2d 数组转换为锯齿状，然后使用 Linq ：

var array = new string[,] {
  {"A", "B", "C"},
  {"D", "E", "F"},
  {"G", "H", "I"},
  {"J", "K", "L"},
};

File.WriteAllLines(@"C:\MyFile.txt", array
  .ToJagged()
  .Select(line => String.Join(" ", line));

Answer 2

假设x和y两个维度。

和一个数组类似于[x，y]

将x和y启动为0
逐一递增y [x，y ++]
在y的结尾（当X已经消耗了所有y时），打印a 新行字符
将x增加一个
继续

Answer 3

    static void Main(string[] args)
    {
        var array = new string[4, 3];
        array[0, 0] = "A";
        array[0, 1] = "B";
        array[0, 2] = "C";
        array[1, 0] = "D";
        array[1, 1] = "E";
        array[1, 2] = "F";
        array[2, 0] = "G";
        array[2, 1] = "H";
        array[2, 2] = "I";
        array[3, 0] = "J";
        array[3, 1] = "K";
        array[3, 2] = "L";

        using (var sw = new StreamWriter("outputText.txt"))
        {
            for (int i = 0; i < 4; i++)
            {
                for (int j = 0; j < 3; j++)
                {
                    sw.Write(array[i,j] + " ");
                }
                sw.Write("\n");
            }

            sw.Flush();
            sw.Close();
        }
    }

如何将多维数组的值写入文本文件

3 个答案: