我实现了这种方法，当在文本字段中输入无根字符或已经使用的用户名时，向用户发送一些警报视图：
func textFieldShouldEndEditing(textField: UITextField) -> Bool {
let acceptedChars = NSCharacterSet(charactersInString: "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890_")
var isTaken: Bool = false
for c in usernameTxt.text.utf16 {
if !acceptedChars.characterIsMember(c) {
let myAlert = SCLAlertView().showError("Woah There", subTitle: "username can only contain uppercase & lowercase letters A-Z,numbers 0-9, or the special character(s) _", closeButtonTitle: "Got It")
myAlert.alertview.contentView.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.circleBG.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.labelTitle.textColor = UIColor.whiteColor()
myAlert.alertview.contentView.layer.borderColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0).CGColor
myAlert.alertview.viewText.textColor = UIColor.whiteColor()
myAlert.alertview.viewText.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
signSecond.userInteractionEnabled = false
signSecond.highlighted = true
textField.resignFirstResponder()
return true
}else {
signSecond.userInteractionEnabled = true
signSecond.highlighted = false
}
}; for b in passwordTxt.text.utf16 {
if !acceptedChars.characterIsMember(b) {
let myAlert = SCLAlertView().showError("Woah There", subTitle: "password can only contain uppercase & lowercase letters A-Z,numbers 0-9, or the special character(s) _", closeButtonTitle: "Got It")
myAlert.alertview.contentView.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.circleBG.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.labelTitle.textColor = UIColor.whiteColor()
myAlert.alertview.contentView.layer.borderColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0).CGColor
myAlert.alertview.viewText.textColor = UIColor.whiteColor()
myAlert.alertview.viewText.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
signSecond.userInteractionEnabled = false
signSecond.highlighted = true
textField.resignFirstResponder()
return true
}else {
signSecond.userInteractionEnabled = true
signSecond.highlighted = false
}
}; for a in confirmTxt.text.utf16 {
if !acceptedChars.characterIsMember(a) {
let myAlert = SCLAlertView().showError("Woah There", subTitle: "password confirmation can only contain uppercase & lowercase letters A-Z,numbers 0-9, or the special character(s) _", closeButtonTitle: "Got It")
myAlert.alertview.contentView.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.circleBG.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.labelTitle.textColor = UIColor.whiteColor()
myAlert.alertview.contentView.layer.borderColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0).CGColor
myAlert.alertview.viewText.textColor = UIColor.whiteColor()
myAlert.alertview.viewText.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
signSecond.userInteractionEnabled = false
signSecond.highlighted = true
textField.resignFirstResponder()
return true
}else {
signSecond.userInteractionEnabled = true
signSecond.highlighted = false
}
};
var query = PFQuery(className: "_User")
query.whereKey("username", equalTo: usernameTxt.text)
query.findObjectsInBackgroundWithBlock {
(objects: [AnyObject]?, error: NSError?) in
if error == nil {
if (objects!.count > 0){
isTaken = true
let myAlert = SCLAlertView().showError("Woah There", subTitle: "username \(self.usernameTxt.text) is already taken", closeButtonTitle: "Got It")
myAlert.alertview.contentView.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.circleBG.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.labelTitle.textColor = UIColor.whiteColor()
myAlert.alertview.contentView.layer.borderColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0).CGColor
myAlert.alertview.viewText.textColor = UIColor.whiteColor()
myAlert.alertview.viewText.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
} else {
println("Username is available. ")
}
} else {
println("error")
}
}
textField.resignFirstResponder()
return true
}
现在，当我输入无效字符串并点击下一个文本字段时，警报视图会相应显示。但是，当我回到原始文本字段以纠正错误时，问题就出现了，警报视图再次显示，我不想要。事实上，如果文本字段中存在无效字符串，并且我选择任何按钮或视图上交互的任何其他位置，则即使选择了取消按钮，也会弹出警告。我该如何解决这个问题？
答案 0 :(得分：2)
问题是为每个文本字段调用了文本字段委托方法。但是您已经编写了textFieldShouldEndEditing方法来检查每个文本字段。
修改委托方法，使其仅检查您当前要离开的文本字段。这是尝试相应地更新您的代码。请注意，我不知道Swift所以我可能有一些语法错误，但它应该给你正确的想法。
func textFieldShouldEndEditing(textField: UITextField) -> Bool {
let acceptedChars = NSCharacterSet(charactersInString: "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890_")
var isTaken: Bool = false
for c in textField.text.utf16 {
if !acceptedChars.characterIsMember(c) {
let myAlert = SCLAlertView().showError("Woah There", subTitle: "field can only contain uppercase & lowercase letters A-Z,numbers 0-9, or the special character(s) _", closeButtonTitle: "Got It")
myAlert.alertview.contentView.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.circleBG.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.labelTitle.textColor = UIColor.whiteColor()
myAlert.alertview.contentView.layer.borderColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0).CGColor
myAlert.alertview.viewText.textColor = UIColor.whiteColor()
myAlert.alertview.viewText.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
signSecond.userInteractionEnabled = false
signSecond.highlighted = true
return false // don't leave since it's invalid
}else {
signSecond.userInteractionEnabled = true
signSecond.highlighted = false
}
};
var query = PFQuery(className: "_User")
query.whereKey("username", equalTo: textField.text)
query.findObjectsInBackgroundWithBlock {
(objects: [AnyObject]?, error: NSError?) in
if error == nil {
if (objects!.count > 0){
isTaken = true
let myAlert = SCLAlertView().showError("Woah There", subTitle: "username \(textField.text) is already taken", closeButtonTitle: "Got It")
myAlert.alertview.contentView.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.circleBG.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
myAlert.alertview.labelTitle.textColor = UIColor.whiteColor()
myAlert.alertview.contentView.layer.borderColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0).CGColor
myAlert.alertview.viewText.textColor = UIColor.whiteColor()
myAlert.alertview.viewText.backgroundColor = UIColor(red:1.0, green:0.18, blue:0.18, alpha:1.0)
return false; // invalid, don't leave
} else {
println("Username is available. ")
}
} else {
println("error")
}
}
return true
}
上面的代码没有关于你需要自己解决的问题，那就是要解析的查询。目前检查“用户名”值的值是硬编码。但它应该根据当前文本字段检查字段。
另请注意，当文本字段值无效时，我如何更改委托方法以返回false。这可以防止用户留下无效的文本字段。