Question

我有一个多次包含相同用户ID的表。

我想返回9个用户名最多的用户的图片。

如何选择行数最多的用户和从最多到最少的用户？

这可能很容易，但我找不到答案。

$sql ="SELECT * FROM beoordelingen,users WHERE beoordelingen.userid=users.userid
GROUP BY beoordelingen.userid LIMIT 9 ";
$result = $conn->query($sql) or die ("The query could not be completed. try again");

$cols=3;
    echo "<table width='150' border='0' cellpadding='0'>";  // The container table with $cols columns
do{
    echo "<tr>";
    for($i=1;$i<=$cols;$i++){   // All the rows will have $cols columns even if
                                // the records are less than $cols
    $row=mysqli_fetch_array($result);
    if($row){
            echo"<td> 
            <table width='150' border='0' cellpadding='0'>
            ";
    if ($row["userimage"] == '') {
            echo "<a href='user.php? id=" . $row['userid'] . "'</a><img src='Images/users/nopicture.png' alt='nopicture'
            class='userimage-tooltip-large' title='".$row['username']."''>";
    } else {
            echo "<a href='user.php? id=" . $row['userid'] . "'</a><img src='Images/users/".$row['userimage']."'
            class='userimage-tooltip-large' title='".$row['username']."''>";
    }
            echo"</table>
            </td>";
    } else {
            echo "<td>&nbsp;</td>"; //If there are no more records at the end, add a blank column

    }
    }
    } while($row);
    echo "</table>";

Answer 1

使用userid添加行数，按降序排序，然后使用限制： -

SELECT users.userimage, 
        users.userid,
        users.username,
        COUNT(*) AS userid_count
FROM beoordelingen
INNER JOIN users 
ON beoordelingen.userid=users.userid
GROUP BY beoordelingen.userid 
ORDER BY userid_count DESC
LIMIT 9

请注意，未定义除userid之外的列的值。如果你想要特定行的值，那么这有点复杂，你需要定义哪一个。

SELECT userinformation其中userid位于最多行中

1 个答案: