Question

概述：我想通过输入参数startdate和enddate显示每周结果。我得到的结果非常好。但问题是，当我想从2015年8月28日开始约会结束日期04/09/2015上午从同月（8月）获得28,29,30,31,01,02,03,04。预计结果应为8月28日，29日，30日，31日和9月1日，02日，03日，04日。

帮我解决这个问题。以下是我的代码

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local  all  all              trust
local  all  all 127.0.0.1/32 trust
host   all  all ::1/128      md5

编辑：我试过if if条件，如果（monthdifference等于0） else（monthdifference大于0）。但没有得到预期的结果。

Answer 1

试试这个

Declare
@StartDate datetime='2015/08/28',
@EndDate datetime='2015/09/04'
;WITH sample AS (
  SELECT CAST(@StartDate AS DATETIME) AS dt
  UNION ALL
  SELECT DATEADD(dd, 1, dt)
    FROM sample s
   WHERE DATEADD(dd, 1, dt) <= CAST(@EndDate AS DATETIME))
SELECT * 
  FROM sample

输出是：

2015-08-28 00:00:00.000  
2015-08-29 00:00:00.000  
2015-08-30 00:00:00.000   
2015-08-31 00:00:00.000   
2015-09-01 00:00:00.000   
2015-09-02 00:00:00.000   
2015-09-03 00:00:00.000   
2015-09-04 00:00:00.000

原始链接：https://stackoverflow.com/a/3946151/3465753

Answer 2

确保在动态查询中声明了startdate和enddate

Answer 3

主要想法是：

您不需要使用STUFF。只需从DATEADD（DAY，1，@ startdate）
中选择日期即可
如果DATENAME（MONTH，@ startdate），你应该得到日期twise！= DATENAME（MONTH，@ enddate）。第一次从开始到月末。第二次从第二个月开始到结束。

我的（已选中）脚本。

ALTER PROCEDURE [dbo].[usp_Get_TimesheetDetails]
    @UserID int, @startdate datetime, @enddate datetime
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;

Declare @columns varchar(max);
DECLARE @sqlText nvarchar(1000); 
Declare @temptable table (num date );

     WITH gen AS (
         SELECT DATEADD(DAY,1,@startdate) AS num
         UNION ALL
         SELECT DATEADD(DAY,1,num) FROM gen 
         WHERE DATEADD(DAY,1,num) <= @enddate
      and DATEADD(DAY,1,num) < dateadd(month,datediff(month,0,@enddate),0) 
         )
      insert into @temptable SELECT  num  FROM gen
      option (maxrecursion 10000)

      set @columns=
      (SELECT distinct  
              STUFF((SELECT ',' + CAST( DATEPART(DAY, num) as varchar(100)) [text()]
              FROM @temptable

              FOR XML PATH(''), TYPE)
              .value('.','NVARCHAR(MAX)'),1,1,'') List_Output
              FROM @temptable t)


      SET @sqlText = N'SELECT [' + REPLACE(@columns,',','],[') + ']' + ' FROM dbo.timesheet where month ='''+ DATENAME(MONTH, @startdate)+''' and [Task ID] in(select TaskID from ManageTasks where TeamMemberUserID ='+  Cast(@UserID AS VARCHAR(max)) +')';
      print @sqlText;

    IF  DATENAME(MONTH, @startdate)!=DATENAME(MONTH, @enddate)  
    BEGIN
    delete from @temptable;

     WITH gen AS (
         SELECT dateadd(month,datediff(month,0,@enddate),0)  AS num
         UNION ALL
         SELECT DATEADD(DAY,1,num) FROM gen 
         WHERE DATEADD(DAY,1,num) <= @enddate
         )
     insert into @temptable SELECT  num  FROM gen
      option (maxrecursion 10000)

      set @columns=
      (SELECT distinct  
              STUFF((SELECT ',' + CAST( DATEPART(DAY, num) as varchar(100)) [text()]
              FROM @temptable

              FOR XML PATH(''), TYPE)
              .value('.','NVARCHAR(MAX)'),1,1,'') List_Output
              FROM @temptable t)


      SET @sqlText = N'SELECT [' + REPLACE(@columns,',','],[') + ']' + ' FROM dbo.timesheet where month ='''+ DATENAME(MONTH, @enddate)+''' and [Task ID] in(select TaskID from ManageTasks where TeamMemberUserID ='+  Cast(@UserID AS VARCHAR(max)) +')';
      print @sqlText 
     end
   end

Answer 4

您可能会发现pivot / unpivot更强大。当然你的桌子设计并不理想。（为了演示目的，我减少了列数。）

create table dbo.timesheet (
    [month] varchar(12) not null,
    [1] int null, [2] int null, [3] int null,
    [28] int null, [29] int null, [30] int null, [31] int null
);

declare @startDate date = '20160628';
declare @endDate date = '20160703';

insert into dbo.timesheet ([month], [1], [2], [3], [28], [29], [30], [31])
values ('June', 1, 2, 3, 4, 5, 6, null), ('July', 8, 9, 10, 11, 12, 13, 14);


with hrs as (
select
    hrs,
    dy,
    dateadd(
        month,
        case [month]
            when 'January' then 1 when 'February' then 2 when 'March' then 3
            when 'April' then 4 when 'May' then 5 when 'June' then 6
            when 'July' then 7 when 'August' then 8 when 'September' then 9 
            when 'October' then 10 when 'November' then 11 when 'December' then 12
        end,
        dateadd(year, year(getdate()) - 2000, dateadd(day, dy - 1, '19991201'))
    ) as dt
from
    (select [month], [1], [2], [3], [28], [29], [30], [31] from dbo.timesheet) t
    unpivot (hrs for dy in ([1], [2], [3], [28], [29], [30], [31])) as upvt
)
select datename(month, dt), [1], [2], [3], [28], [29], [30], [31]
from hrs pivot (min(hrs) for dy in ([1], [2], [3], [28], [29], [30], [31])) as pvt
where dt between @startDate and @endDate;

存储过程中的日期函数

4 个答案: