在Swift中推送iOS8的通知状态

时间:2015-08-19 06:57:58

标签: ios swift push-notification

我一直在寻找一个关于在Swift for iOS8中设置推送通知的正确教程,但我觉得从Objective-C到Swift和iOS7到iOS8已经做了很多改变,尽管我找不到任何更新了一段代码。

我想知道用户是否已经按下了“不允许"推送通知提醒中的按钮和/ 或者他们曾经看过它

事实是,在这种情况下,我希望显示一条警告,要求用户通过设置实现通知。

问题:我不知道要检查哪个变量,以确定我是否应该显示弹出窗口。

我可以使用这个但是在两个从未显示1-推送通知警报的情况下,哈希值为0,显示了2-推送通知警报,但是用户已经按下了#34;不允许"。

if(UIApplication.sharedApplication().currentUserNotificationSettings().hashValue == 0){
            pushNotificationStatus = "false"
        } else {
            pushNotificationStatus = "true"
        }

您是否有任何最佳实践/想法来解决这个问题? 谢谢你!

2 个答案:

答案 0 :(得分:0)

//Write belkow code in Appdelegate.m in didfinishLaunching mehod..

  Register for Push Notitications, if running iOS 8
if application.respondsToSelector("registerUserNotificationSettings:") {

  let types:UIUserNotificationType = (.Alert | .Badge | .Sound)
  let settings:UIUserNotificationSettings = UIUserNotificationSettings(forTypes: types, categories: nil)

  application.registerUserNotificationSettings(settings)
  application.registerForRemoteNotifications()

} else {      
  // Register for Push Notifications before iOS 8
  application.registerForRemoteNotificationTypes(.Alert | .Badge | .Sound)
}

你可以进入didFailToRegisterForRemoteNotificationsWithError

  func application(
        application: UIApplication,
        didRegisterForRemoteNotificationsWithDeviceToken deviceToken: NSData
    ) {


         //Process the deviceToken and send it to your server
         let trimEnds = {
          deviceToken.description.stringByTrimmingCharactersInSet(
          NSCharacterSet(charactersInString: "<>"))
            }
         let cleanToken = {
          trimEnds.stringByReplacingOccurrencesOfString(
           " ", withString: "", options: nil)
           }
        }

    func application(
        application: UIApplication,
        didFailToRegisterForRemoteNotificationsWithError error: NSError
    ) {
        //Log an error for debugging purposes, user doesn't need to know
        NSLog("Failed to get token; error: %@", error) 
    }

在接收委托后的通知将致电:

func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject]) {

    println("Recived: \(userInfo)")
   //Parsing userinfo:
   var temp : NSDictionary = userInfo
   if let info = userInfo["aps"] as? Dictionary<String, AnyObject> 
            {
                var alertMsg = info["alert"] as! String
                var alert: UIAlertView!
                alert = UIAlertView(title: "", message: alertMsg, delegate: nil, cancelButtonTitle: "OK")
                alert.show()
            }
}

你可以控制UIApplication.sharedApplication()的哈希值.currentUserNotificationSettings()。

if(UIApplication.instancesRespondToSelector(Selector("registerUserNotificationSettings:"))){
        if(UIApplication.sharedApplication().currentUserNotificationSettings().hashValue == 0){
            pushNotificationStatus = "false"
        } else {
            pushNotificationStatus = "true"
        }
}

答案 1 :(得分:0)

从iOS 10.0开始,您可以使用此方法

UNUserNotificationCenter.current().getNotificationSettings(completionHandler:  { settings in
     switch settings.authorizationStatus {
     case .notDetermined:
         print("Not determined")
     case .denied: //In this case user has already seen this alert, and answered "Don't allow"
         print("Denied") 
     case .authorized:
         print("Authorised")
}