Mysql - 选择where where子句和附加条件？

Question

这是表格：

* rulestbl

|  idrule  |  idsys  |  orders |
--------------------------------
|R01#1     |    1    |    1    |
|R01#1     |    2    |    1    |
|R01#2     |    1    |    2    |
|R01#2     |    3    |    2    |
|R01#2     |    4    |    2    |
|R01#3     |    2    |    3    |
|R01#3     |    1    |    3    |
|R01#3     |    5    |    3    |
|R01#4     |    1    |    4    |
|R01#4     |    4    |    4    |
|R01#4     |    5    |    4    |
--------------------------------

我想在一个输入数组中选择2个条件，如果我想输入（idsys = 1和idsys = 2）和"where orders" = MIN()，那么输出应为：

|  idrule  |  orders  |
----------------------
|R01#1     |   1     |
----------------------

谁能帮帮我？感谢

结果应该只消除“idsys with conditon 1 and 2”，所以结果应该是：

|   idrule  |  orders  |
-----------------------
|R01#1      |    1    |
|R01#3      |    3    |
-----------------------

这是首次消除的语法：

SELECT idrule
FROM rulestbl
WHERE idsys IN (1, 2)
GROUP BY idrule
HAVING count(*) = 2

所以接下来我们消除MIN（顺序）是1所以最终的结果是：

|   idrule  |  orders  |
------------------------
|R01#1      |    1     |
------------------------

Answer 1

这应该有用; - ）

SELECT X.IDRULE, MIN(X.ORDERS) FROM rulestbl,
(
SELECT idrule, orders
FROM rulestbl
WHERE idsys IN (1, 2)
GROUP BY idrule
HAVING count(*) = 2
) X
WHERE X.idrule = rulestbl.idrule

在IN子句中，您可以拆分数组。

祝你好运